Do something every x iterations

[Infiniti]

Lets say I have an xml file as such

<page>
<chapter>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
</chapter>
</page>

And in my XSL file I want to do something every x occurances of the
paragraph element to end up with something like this. How can I match this ?

[Infiniti]

Lets say I have an xml file as such <page>
<chapter>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
</chapter>
</page> And in my XSL file I want to do something every x occurances of the
paragraph element to end up with something like this. How can I match
this ?

I missed off the example there, but I want to take such an XML file and
apply a stylesheet to get something like this

[page name]
[chapter name]
Three Paragraphs
[paragraph]
[paragraph]
[paragraph]
Three Paragraphs
[paragraph]
[paragraph]
[paragraph]

etc.

[Infiniti]

Ok I understand that thanks. One thing that makes it more complex is that
the paragraph elements all have different names. I.e., mix of tags, but all
need to be treated as a group.

Hi, Try something like... <?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:param name="grp-size" select="3"/>
<xsl:template match="page">
<xsl:text>[page name] </xsl:text>
<xsl:apply-templates select="chapter"/>
</xsl:template> <xsl:template match="chapter">
<xsl:text>[chapter name] </xsl:text>
<!-- do every n'th paragraph -->
<xsl:apply-templates select="paragraph[position() mod $grp-size = 1
or $grp-size = 1]" mode="grp-start"/>
</xsl:template> <xsl:template match="paragraph" mode="grp-start">
<xsl:value-of select="$grp-size"/>
<xsl:text> paragraphs </xsl:text>
<!-- aplly to this and next n < size -->
<xsl:apply-templates select=". |
following-sibling::paragraph[position()
&lt; $grp-size]"/>
</xsl:template> <xsl:template match="paragraph">
<xsl:text>[paragraph] </xsl:text>
</xsl:template>
</xsl:stylesheet> Hope this helps
Marrow http://www.marrowsoft.com - home of Xselerator (XSLT IDE and
debugger)
http://www.topxml.com/Xselerator "Infiniti" <an*********@nodomain.com> wrote in message
news:o-********************@giganews.com...

Lets say I have an xml file as such <page>
<chapter>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
<paragraph/>
</chapter>
</page> And in my XSL file I want to do something every x occurances of the
paragraph element to end up with something like this. How can I match
this

?

[Infiniti]

Hi,

Ok I understand that thanks. One thing that makes it more complex is
that the paragraph elements all have different names. I.e., mix of
tags, but

all

need to be treated as a group.

Show an example of the actual XML? ;)

I have components like textbox, etc in the XML file that is generated
automatically from my Java code, and then an XSL stylesheet is applied to
turn it into html files. I can write admin pages for my web site in seconds.
However I wanted to lay out the components in tables, but for that I needed
the above code. I shall just change my code so that all the elements are
like such

<component type="textbox"> instead of <textbox>

[Infiniti]

Hi,

Ok I understand that thanks. One thing that makes it more complex is
that the paragraph elements all have different names. I.e., mix of
tags, but

all

need to be treated as a group.

Show an example of the actual XML? ;)

It's all working now except when I use 1 as the variable. Then it doesn't
seem to match anything. This is related to the question I just posted.

[Buchleitner Martin]

On Tue, 8 Jul 2003 11:05:11 +0100, "Infiniti"
<an*********@nodomain.com> wrote:

Hi!

does position() begin at 0 or 1 ?
It starts with 1 ..
How can I output

position() mod $variable to the screen ?

I'd say...
<xsl:value-of select="position() mod $variable"/>
....should work - it does with XMLSpy ...

Martin

[Marrow]

Hi,

Another question,

does position() begin at 0 or 1 ?
position() is 1 based.
How can I output

position() mod $variable to the screen ?

If I put it inside a value-of block it doesn't do anything.
Probably because position() is subtely different when used inside or outside
a predicate (i.e. [] square brackets).

For example, when you use position() within a predicate like...

<xsl:apply-templates select="somenodes[position() mod 3 = 1]"/>

the position() function returns the position of each node within the
node-set selected by the 'somenodes' part.

Whereas, if you do...

<xsl:value-of select="position()"/>

the position() function is returning the position within the currently
selected (applied or for-each) node-set.

Cheers
Marrow
"Infiniti" <an*********@nodomain.com> wrote in message
news:II********************@giganews.com...

> Hi,

>> Ok I understand that thanks. One thing that makes it more complex is
>> that the paragraph elements all have different names. I.e., mix of
>> tags, but

> all

>> need to be treated as a group.

> Show an example of the actual XML? ;)

Another question,

does position() begin at 0 or 1 ?

How can I output

position() mod $variable to the screen ?

If I put it inside a value-of block it doesn't do anything.