typeid problems -- _non_r

[ezelasky]

I am programming in microsoft VC++ 7.1 and get an unhandled exception
when I use typeid on a deferenced pointer.

So I tried the example below, from the msdn site and I am seeing the
same error as with my code, "Unhandled exception ...
__non_rtti_object__".

Perhaps I am missing a setting or something in my environment?

Thanks, Elizabeth

class Base {
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

Derived1* pd = new Derived1;
Base* pb = pd;
cout << typeid( *pb ).name() << endl;
delete pd;
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[Bruno van Dooren]

you have to compile with run-time type information enabled:
right-click your project, select configuration properties ->
c/c++ ->language and set 'enable run time type info' to yes.

that will solve it.

for more info look for 'typeid operator' in MSDN.

kind regards,
Bruno.

<ez******@hotmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

I am programming in microsoft VC++ 7.1 and get an unhandled exception
when I use typeid on a deferenced pointer.

So I tried the example below, from the msdn site and I am seeing the
same error as with my code, "Unhandled exception ...
__non_rtti_object__".

Perhaps I am missing a setting or something in my environment?

Thanks, Elizabeth

class Base {
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

Derived1* pd = new Derived1;
Base* pb = pd;
cout << typeid( *pb ).name() << endl;
delete pd;
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[Mikhail Kubzin]

Did you enable RTTI in Project - Properties - C/C++ - Language - Enable
Runtime Type Info (/GR option of the compiler)?

Regards,
Mikhail

ez******@hotmail.com wrote:

I am programming in microsoft VC++ 7.1 and get an unhandled exception
when I use typeid on a deferenced pointer.

So I tried the example below, from the msdn site and I am seeing the
same error as with my code, "Unhandled exception ...
__non_rtti_object__".

Perhaps I am missing a setting or something in my environment?

Thanks, Elizabeth

class Base {
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

Derived1* pd = new Derived1;
Base* pb = pd;
cout << typeid( *pb ).name() << endl;
delete pd;

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[Michiel.Salters]

[e-mail] wrote:

I am programming in microsoft VC++ 7.1 and get an unhandled exception
when I use typeid on a deferenced pointer. .... __non_rtti_object__".

Perhaps I am missing a setting or something in my environment?
Just a guess: you have turned off RTTI ? Standard C++ requires RTTI
features,
but the Microsoft compiler allows you to turn them off. A useless
option IMO
(if you want to cut the overhead, remove it during linking) which just
makes
testing double the work for them.

Of course, in that case easch object is a non-RTTI object, but I'd
expect the
compiler to reject typeid as well.

HTH,
Michiel Salters
class Base {
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

Derived1* pd = new Derived1;
Base* pb = pd;
cout << typeid( *pb ).name() << endl;
delete pd;

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[Jim Langston]

<ez******@hotmail.com> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

I am programming in microsoft VC++ 7.1 and get an unhandled exception
when I use typeid on a deferenced pointer.

So I tried the example below, from the msdn site and I am seeing the
same error as with my code, "Unhandled exception ...
__non_rtti_object__".

Perhaps I am missing a setting or something in my environment?

Thanks, Elizabeth

class Base {
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

Derived1* pd = new Derived1;
Base* pb = pd;
cout << typeid( *pb ).name() << endl;
delete pd;

The following program compiles and runs and produces the output
class Derived1
in Microsoft Visual C++ .net 2003

#include <iostream>
#include <string>

class Base
{
public:
virtual void vvfunc() {}
};

class Derived1 : public Base {};

int main()
{
Derived1* pd = new Derived1;
Base* pb = pd;
std::cout << typeid( *pb ).name() << std::endl;
delete pd;
std::string Wait;
std::cin >> Wait;
}
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