Hi;
Once I have loaded an xml file into a DOM, is there any way to then get any
namespace declarations that were in the xml file? Or are those just discarded
as the DOM is populated?
And if you can't get it from the DOM, any other way to get the namespace(s)?
I'm assuming doing a SAX read which returns each element including NameSpaces
and pull it form that (and build up the DOM at the same time)?
In my case I get a Stream so I can't read it twice as the Stream may not
support reset. And it may have NS elements - but I don't know if there are
any or what they are except by reading the Stream.
--
thanks - dave 11 4349
David Thielen wrote: Once I have loaded an xml file into a DOM, is there any way to then get any namespace declarations that were in the xml file? Or are those just discarded as the DOM is populated?
Of course not. You can select namespace declarations using
doc.SelectNodes ("//namespace::*").
--
Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com
Hi;
This sort-of worked. I have 3 namespaces declared in the header of the file.
The SelectNodes("//namespace::*") gave me 36 nodes. I did not check each one
but it appeared to be the 3 namespaces repeated over and over.
Any idea why I didn't get just 3?
--
thanks - dave
"Oleg Tkachenko [MVP]" wrote: David Thielen wrote:
Once I have loaded an xml file into a DOM, is there any way to then get any namespace declarations that were in the xml file? Or are those just discarded as the DOM is populated?
Of course not. You can select namespace declarations using doc.SelectNodes ("//namespace::*").
-- Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com
For the xml:
<root xmlns="http://www.test.org" xmlns:sns="http ://www.test.org/sub"
xmlns:mns="http ://www.test.org/mini">
<data>
<items>
<item id="1">
<sns:subItem sid="11">dave</sns:subItem>
<sns:subItem sid="12">thiele n</sns:subItem>
</item>
<item id="2">
<sns:subItem sid="21">shirle y</sns:subItem>
</item>
</items>
<mns:more>dav e thielen</mns:more>
</data>
</root>
The nodes returned are:
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
mns=http://www.test.org/mini
sns=http://www.test.org/sub
{default}=http://www.test.org
xml=http://www.w3.org/XML/1998/namespace
??? - thanks - dave
David Thielen wrote: This sort-of worked. I have 3 namespaces declared in the header of the file. The SelectNodes("//namespace::*") gave me 36 nodes. I did not check each one but it appeared to be the 3 namespaces repeated over and over.
Any idea why I didn't get just 3?
Because in the XPath data model any element has in scope namespace nodes
and that way if you for instance declare namespaces on the root element
and do not declare/redeclare namespaces on any child elements then
besides the root element all child elements also have those namespaces
in scope as nodes of their own.
--
Martin Honnen --- MVP XML http://JavaScript.FAQTs.com/
David Thielen wrote: This sort-of worked. I have 3 namespaces declared in the header of the file. The SelectNodes("//namespace::*") gave me 36 nodes. I did not check each one but it appeared to be the 3 namespaces repeated over and over.
Any idea why I didn't get just 3?
Select unique ones (and omit default "xml" namespace):
//namespace::*[name() != 'xml'][not(../../namespace::*=.)]
--
Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com
Oh right, that makes a lot of sense -- thanks - dave
"Martin Honnen" wrote:
David Thielen wrote:
This sort-of worked. I have 3 namespaces declared in the header of the file. The SelectNodes("//namespace::*") gave me 36 nodes. I did not check each one but it appeared to be the 3 namespaces repeated over and over.
Any idea why I didn't get just 3?
Because in the XPath data model any element has in scope namespace nodes and that way if you for instance declare namespaces on the root element and do not declare/redeclare namespaces on any child elements then besides the root element all child elements also have those namespaces in scope as nodes of their own.
--
Martin Honnen --- MVP XML http://JavaScript.FAQTs.com/
Hi;
This worked great but I don't understand it totally. I get the [name() !=
'xml']
But what does [not(../../namespace::*=.)] mean? I'm totally lost on how that
works.
Also, when you do xpath[a][b] is that saying both a and b must be true? Can
you also do //namespace::*[name() != 'xml'] and [not(../../namespace::*=.)]
as the same thing? Or am I not understanding this?
I'm asking the above questions because I just want to understand xpath better.
--
thanks - dave
"Oleg Tkachenko [MVP]" wrote: David Thielen wrote:
This sort-of worked. I have 3 namespaces declared in the header of the file. The SelectNodes("//namespace::*") gave me 36 nodes. I did not check each one but it appeared to be the 3 namespaces repeated over and over.
Any idea why I didn't get just 3?
Select unique ones (and omit default "xml" namespace): //namespace::*[name() != 'xml'][not(../../namespace::*=.)]
-- Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com
David Thielen wrote: But what does [not(../../namespace::*=.)] mean? I'm totally lost on how that works.
In XPath data model namespace nodes are propagated/copied down the tree
- each node in a subtree has namespace node for each namespace in context.
This predicate checks that parent of the element bearing the namespace
node doesn't have such namespace node. Effectively that allows to select
only namespace nodes on elements where namespace is declared. Also, when you do xpath[a][b] is that saying both a and b must be true?
Yes.
Can you also do //namespace::*[name() != 'xml'] and [not(../../namespace::*=.)] as the same thing? Or am I not understanding this?
Yes, that's the same.
--
Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com
Hi;
Ok, that makes sense. To make sure I understand this:
.../../namespace::* is getting the grandparent of the node on (../../) and
then getting any nodes in that element that start with namespace:: - why not
.../namespace::* - isn't that the parent?
And then the =. is saying equal to the node presently on . being the node on.
Is that correct?
--
thanks - dave
"Oleg Tkachenko [MVP]" wrote: David Thielen wrote:
But what does [not(../../namespace::*=.)] mean? I'm totally lost on how that works.
In XPath data model namespace nodes are propagated/copied down the tree - each node in a subtree has namespace node for each namespace in context. This predicate checks that parent of the element bearing the namespace node doesn't have such namespace node. Effectively that allows to select only namespace nodes on elements where namespace is declared.
Also, when you do xpath[a][b] is that saying both a and b must be true?
Yes.
Can you also do //namespace::*[name() != 'xml'] and [not(../../namespace::*=.)] as the same thing? Or am I not understanding this?
Yes, that's the same.
-- Oleg Tkachenko [XML MVP, MCAD] http://www.xmllab.net http://blog.tkachenko.com This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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