Select last 3 items in ascending order

[Nick Weisser]

Hi there,

I'm not sure how to select the last 3 items in ascending order.

This does the trick in descending order:

select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3

Your comments would be very much appreciated.

Cheers,
Nick

[strawberry]

Nick Weisser wrote:

Hi there,

I'm not sure how to select the last 3 items in ascending order.

This does the trick in descending order:

select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3

Your comments would be very much appreciated.

Cheers,
Nick

i'm guessing that 'desc' bit's got something to do with it

[Nick Weisser]

strawberry wrote:

i'm guessing that 'desc' bit's got something to do with it

But this will not select the 3 last items in ascending order, but the
first 3!

[Thomas Bartkus]

"Nick Weisser" <ni**@nospam.freemails.chwrote in message
news:44**********@news.bluewin.ch...

Hi there,

I'm not sure how to select the last 3 items in ascending order.

This does the trick in descending order:

select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3

Your comments would be very much appreciated.

That problem is a natural for a temporary table.

create temporary table tmp
select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3;

select * from tmp
order by date desc;

Thomas Bartkus

[strawberry]

Thomas Bartkus wrote:

"Nick Weisser" <ni**@nospam.freemails.chwrote in message
news:44**********@news.bluewin.ch...

Hi there,

I'm not sure how to select the last 3 items in ascending order.

This does the trick in descending order:

select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3

Your comments would be very much appreciated.

That problem is a natural for a temporary table.

create temporary table tmp
select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3;

select * from tmp
order by date desc;

Thomas Bartkus

I see, you want to limit your select to last three items of a list, but
have those items listed in the ordinary order. Well Thomas's solution
is probably the most straightfoward, although (depending on your
version) you don't actually need to create the temporary table:

(untested)

select * from (
select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3) tmp
order by date asc;

[Thomas Bartkus]

"strawberry" <za*******@gmail.comwrote in message
news:11**********************@i3g2000cwc.googlegro ups.com...

>
Thomas Bartkus wrote:

"Nick Weisser" <ni**@nospam.freemails.chwrote in message
news:44**********@news.bluewin.ch...

Hi there,
>
I'm not sure how to select the last 3 items in ascending order.
>
This does the trick in descending order:
>
select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3
>
Your comments would be very much appreciated.
>

That problem is a natural for a temporary table.

create temporary table tmp
select * from user_menu_main
where deleted = 0 and hidden = 0
order by date desc
limit 3;

select * from tmp
order by date desc;

Thomas Bartkus

I see, you want to limit your select to last three items of a list, but
have those items listed in the ordinary order. Well Thomas's solution
is probably the most straightfoward, although (depending on your
version) you don't actually need to create the temporary table:

... you don't actually need to create the temporary table:

On the other hand - there ain't no reason not to ;-)

That subquery you show, for instance, uses a temporary table behind the
scenes.
Thomas Bartkus