Urgently need help for school program please help

[max3]

Hi to all I'am trying to run this program for my school progect but I keep receiving the same answer when I compile ')' expected. on the highlighted line can anyone help me thanks to all.



/**
* Write a description of class Records here.
*
* @author (Ryan MIfsud)
* @version (version 1)
*/
public class Records
{


public static void main (String Args []){

String Student_Name1;
String Student_surname1;
String Student_ID1;
String Student_group1;
System.out.println ("Enter name ");
int name = Keyboard.readInt();
char grade;

grade = '_';

if ( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle || name < Kurt) System.out.println ("name is not included");
else
if (name >= Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle && name <= Kurt )
grade = 'name included';



System.out.println ( "Enter student's name" );
Student_Name1 = Keyboard.readString();

System.out.println ( "Enter student's surname" );
Student_surname1 = Keyboard.readString();

System.out.println( "Enter student's ID" );
Student_ID1 = Keyboard.readString();

System.out.println( "Enter student's group" );
Student_group1 = Keyboard.readString();

System.out.println ( Student_Name1 + Student_surname1 + Student_ID1 + Student_group1 );

System.out.println ("End by entering -1");
int counter = -1;


}

}

[blazedaces]

Hey, from now on please put your code in code tags (look on the right when you post on the box that says "REPLY GUIDELINES". Also, could you post the full error you get when you try to compile. I'm a bit confused as to what exactly it's trying to tell you...

-blazed

[r035198x]

if (name >= Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle && name <= Kurt )
grade = 'name included';


Those two lines will not compile. What are you trying to do there?
Also char variable can only hold chars.

[max3]

I'am trying to creat a program that when I give name ,surname and Id in the list it will give me the name and when it is not in the list it will say name not included thanks for your interest and sorry to Blazedaces about the the codes but I'm still new in this fourm and did't understand exactly how the codes work thank you

When I compile this is what I get ')' expected

[blazedaces]

I'am trying to creat a program that when I give name ,surname and Id in the list it will give me the name and when it is not in the list it will say name not included thanks for your interest and sorry to Blazedaces about the the codes but I'm still new in this fourm and did't understand exactly how the codes work thank you

When I compile this is what I get ')' expected

I don't think you can compare more then one result by separating it by a comma like that. I don't think this is possible: name < firstVariable, secondVariable. I think you need to do name < firstVariable && name < secondVariable.

The compiler may think the comma indicates some end for the if statement and wants you to close the parenthesis or something. Also, as mentioned by r035198x above, are you comparing characters or is name and those variables simply integers or something?

Why are you using < to find out if the name is not included in the list?

-blazed

[max3]

Hi I'm only trying to find a selective name out of the list and regarding using this symbol < I think it's the best in my opinion have you any suggestions? thanks what in your opinion should I do to make this program work.

[blazedaces]

Hi I'm only trying to find a selective name out of the list and regarding using this symbol < I think it's the best in my opinion have you any suggestions? thanks what in your opinion should I do to make this program work.

The "<" symbol compares two numbers and if the first is "less than" the other, it returns true, otherwise it returns false... How does this have anything to do with finding a selective name out of the list?

If you asked a random person "is Jake less then Ronald" they would ask you what you're talking about, which is exactly what the JVM will do.

What I think you should do is go through the entire list one at a time and ask "is Jake the same name as ronald?" no, repeat throughout the entire list. Use the String1.equals(String2) method...

Good luck,
-blazed

[r035198x]

Hi I'm only trying to find a selective name out of the list and regarding using this symbol < I think it's the best in my opinion have you any suggestions? thanks what in your opinion should I do to make this program work.

Have you read a tutorial about how that symbol is used?

[max3]

R035198 the < symbol means less than and I think it is one of the problems I have I try to change as blazedaces said and tell you what happend later .thanks

[JosAH]

if ( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle || name < Kurt)

Don't just guess what Java's syntax is supposed to be according to what you
wish it to be. Compare it to this: suppose I have my own private understanding
of what a 'fronobulax' is supposed to be. Nobody else would understand me if
I'd ask anyone where to buy fresh fronobulaxes. If you want to program in Java
you have to speak the Java language. When in Rome, do as the Romans do.

kind regards,

Jos

[ramadeviirrigireddy]

Hi,


I don't know whether this statement which u used is valid or not(if ( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle || name < Kurt) ). But what i suggest is write like this [if (( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle) || (name < Kurt) )] when ever u use this || or && operators.

Hi all let me know if i'm wrong.

[JosAH]

Hi,


I don't know whether this statement which u used is valid or not(if ( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle || name < Kurt) ). But what i suggest is write like this [if (( name > Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle) || (name < Kurt) )] when ever u use this || or && operators.

Hi all let me know if i'm wrong.

You're wrong ;-)

If those names are comparable using the '<' or '>' operators they need to be
identifiers of primitive numerical type. If they are of type String, those operators
can't be used. The comma operator isn't defined in Java. That 'statement' (mind
the quotes) is completely wrong.

kind regards,

Jos

[emekadavid]

I think from the discussion i gathered this information:
the names you're comparing against are the “accepted” names for this course, group etc therefore the user is limited to just those and has a “closed” outlook to any other, hence the need for an if statement that compares twice against just that list.
The problem: implement this closet in a list such that when a name is to be in this close group, there is a list to compare against. Instead of doing:
if (name > X1, X2 || name < X3 etc) //this is a list, maybe two lists the comparison on greater than and on less than?
Rather do:
If ( list1.contains(name) || list2.contains(name)) then...”name included”.
else ....”name not included” //somewhat simpler and less code.

i wonder what your keyboard class is? Can't find any Keyboard class in the jdk 6 documentation though i believe it refers to user input. Why do you have to readInt this input and then compare against String? No compiler would accept that. Rather read on string and verify on string input since this is name and name should be string, if black is black and never shades of it.

[ramadeviirrigireddy]

thanks Jos for correcting me

[padmavathik]

thanks Jos for correcting me

hi,
you have taken name as integer and names are in string,
they r incompatable types.
compare name with the length of strings and also take all the atrings into an array.
I think taht oparator will not compare more than one so better to take all strings into array.
String [] arr = new String[Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle] ;

for(int i=0;i<arr.size();i++)
{
if(name>(arr.get(i)).length()||name<kurt.length())
System.out.println("not included);
else
if (name >=(arr.get(i)).length()&& name <= Kurt.length() )
grade = 'name included'

}
once try this iam not sure

[blazedaces]

hi,
you have taken name as integer and names are in string,
they r incompatable types.
compare name with the length of strings and also take all the atrings into an array.
I think taht oparator will not compare more than one so better to take all strings into array.
String [] arr = new String[Ryan,Robert,Victor,Jim,Sammy,Leo,Glen,Kyle] ;

for(int i=0;i<arr.size();i++)
{
if(name>(arr.get(i)).length()||name<kurt.length())
System.out.println("not included);
else
if (name >=(arr.get(i)).length()&& name <= Kurt.length() )
grade = 'name included'

}
once try this iam not sure

That won't work ... that is, it will compile but not do what is needed.

The lengths of the names in that array are 4, 6, 6, 3, 5, 3, 4, 4. That means ANY string with a length of 3, 4, 5, or 6 will print that the name is included. He's not checking that it's the correct length, he's checking that the name is included in the list...

-blazed