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java.lang.Array IndexOutOfBound sException

oll3i
679 Contributor
i get
Exception in thread "main" java.lang.Array IndexOutOfBound sException: 2
at Producent.main( producent.java: 605)

when i run it from bat

@start "Supply Chain Management-Producer to Queue" run Producent queue1 queue2 queue3 queue4

maybe you will se something i dont see

Expand|Select|Wrap|Line Numbers
  1. public static void main(String[] args){
  2.  
  3.  
  4.  
  5.         if (args.length < 1 || args.length > 4) {
  6.             System.out.println("usage: <destination> <destination> <destination> <destination>");
  7.             System.exit(1);
  8.         }else {Producent producent=new Producent(args[0],args[1],args[2],args[3]);}
  9.          /// producent.close();
  10.  
  11.       }     
  12. }
  13.  
thank you
Jun 11 '07
22 41051
oll3i
679 Contributor
yes it's Producent producent=new Producent(args[0],args[1],args[2],args[3]); causing the exception on line 607
weird
it works fine with 2 parameters
but i need four for the queues
Jun 11 '07 #11
oll3i
679 Contributor
i bat i have 4 parameters
i checked it to be sure
Jun 11 '07 #12
JosAH
11,448 Recognized Expert MVP
yes it's Producent producent=new Producent(args[0],args[1],args[2],args[3]); causing the exception on line 607 it worked fine with 2 parameters
Well, there you have your solution: you should pass four argument to your main()
method if your constructor expects four arguments; simple as that.

kind regards,

Jos
Jun 11 '07 #13
blazedaces
284 Contributor
Well, there you have your solution: you should pass four argument to your main()
method if your constructor expects four arguments; simple as that.

kind regards,

Jos
He should still have error/exception handling if someone/him inputs less then 4 or maybe more arguments though right? ;)

-blazed
Jun 11 '07 #14
oll3i
679 Contributor
it must be something wrong in bat file cos when i run it
>java Producent q1 q2 q3 q4 it works and app opens
Jun 11 '07 #15
JosAH
11,448 Recognized Expert MVP
He should still have error/exception handling if someone/him inputs less then 4 or maybe more arguments though right? ;)

-blazed
Yep; if the constructor for that class demands four arguments the user better
supply them all four, no more and no less and the code should elegantly bail
out if any other number of arguments is supplied. That entire little problem is
so old; an args.length != 4 test is all that's needed in this example.

kind regards,

Jos
Jun 11 '07 #16
r035198x
13,262 MVP
it must be something wrong in bat file cos when i run it
>java Producent q1 q2 q3 q4 it works and app opens
You just run the bat file without supplying the arguments?
Jun 11 '07 #17
oll3i
679 Contributor
no in bat i 'm passing four arguments that's why i dont know why it happens
Jun 11 '07 #18
JosAH
11,448 Recognized Expert MVP
no in bat i 'm passing four arguments that's why i dont know why it happens
Use the "poor man's debugger": do this at the start of your main method:

Expand|Select|Wrap|Line Numbers
  1. System.out.println("nof args: "+args.length);
  2. for (int i= 0; i < args.length; i++)
  3.    System.out.println(i+": "+args[i];
  4.  
and see what arguments are really passed to your main method. Always give
the bug less and less space to hide; finally you can pinpoint it and remove it.
Just guessing never helped anyone.

kind regards,

Jos
Jun 11 '07 #19
blazedaces
284 Contributor
Use the "poor man's debugger": do this at the start of your main method:

Expand|Select|Wrap|Line Numbers
  1. System.out.println("nof args: "+args.length);
  2. for (int i= 0; i < args.length; i++)
  3.    System.out.println(i+": "+args[i];
  4.  
and see what arguments are really passed to your main method. Always give
the bug less and less space to hide; finally you can pinpoint it and remove it.
Just guessing never helped anyone.

kind regards,

Jos
What's the "rich man's debugger" ?!

This is how I usually debug things...

-blazed
Jun 11 '07 #20

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