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//Create a program that will accept numbers in decimal and display them in either binary, octal or hexadecimal. Use a switch statement to select the option (binary, octal, or hex) picked from the menu and make use of modulus (%) and divide operators.
#include<iostream>
using namespace std;
int menu();
void toBinary();
void toOctal();
void toHex();
int main()
{
int choice = menu();
switch(choice)
{
case (1):
toBinary();
break;
case (2):
toOctal();
break;
case(3):
toHex();
break;
}
return 0;
}
int menu()
{
int choice;
cout << "(>^.^)>==(_)Menu(_)==<(^.^<)" << endl;
cout << "Convert the number from decimal into: " << endl;
cout << "1 Binary" << endl;
cout << "2 Octal" << endl;
cout << "3 Hexadecimal" << endl;
cin >> choice;
return choice;
}
void toBinary()
{
int num;
int total = 0;
cout << "Please enter a decimal: ";
cin >> num;
if(num==1)
{
cout<<"\nMAJOR ERROR USE A NUMBER!!!!!";
}
else
while(num > 0)
{
total = num % 2;
num /= 2;
cout << total << " ";
}
}
void toOctal()
{
int num;
int total = 0;
cout << "Please enter a decimal: ";
cin >> num;
if(num==1)
{
cout<<"\nMAJOR ERROR USE A NUMBER!!!!!";
}
else
while(num > 0)
{
total = num % 8;
num /= 8;
cout << total << " ";
}
}
void toHex()
{
int num,counter,x,a,hex[100];
cout<<"Please enter a decimal: ";
cin>>num;
cout<<"\nThe Decimal number "<<num<<" converts to the Hexadecimal number: ";
for(counter=0;num!=0;counter++)
{
a=num%16;
hex[counter]=a;
num=num/16;
}
for(x=counter-1;x>=0;x--)
{
if (hex[x] > 9)
cout << char('A'+hex[x]-10);
else
cout << hex[x];
}
cout << endl;
}
the results need to be reversed in cout but i do not know how. can you guys please help me go through with this? thank you for taking the time to replying to this post.
