vector::reserve() with value less than current size().

[jason.cipriani]

What is the official word on what happens if I call reserve() on an
std::vector, and specify a capacity that is less than the current
*size* (not capacity) of that vector? Is it supposed to resize() the
vector as well? Or just not modify anything?

Thanks,
Jason

[Joe Gottman]

ja************@gmail.com wrote:

What is the official word on what happens if I call reserve() on an
std::vector, and specify a capacity that is less than the current
*size* (not capacity) of that vector? Is it supposed to resize() the
vector as well? Or just not modify anything?

Thanks,
Jason

reserve() never reduces capacity; it just increases it. Therefore this
is a no-op.

Joe Gottman

[Salt_Peter]

On Nov 18, 8:25 pm, "[e-mail]"
<[e-mail]:

What is the official word on what happens if I call reserve() on an
std::vector, and specify a capacity that is less than the current
*size* (not capacity) of that vector? Is it supposed to resize() the
vector as well? Or just not modify anything?

Thanks,
Jason

The size of the vector is irrelevant. If reserve's arguement is less
than or equal to its capacity, nothing happens. Swap the vector to
(maybe) change its capacity.

[jason.cipriani]

On Nov 18, 8:48*pm, Joe Gottman <[e-mail]:

[e-mail] wrote:

What is the official word on what happens if I call reserve() on an
std::vector, and specify a capacity that is less than the current
*size* (not capacity) of that vector? Is it supposed to resize() the
vector as well? Or just not modify anything?

Thanks,
Jason

reserve() never reduces capacity; it just increases it. *Therefore this
is a no-op.

That's what I was looking for, thanks Joe and Salt_Peter.

Also, sorry, I'm looking now and it turns out that actually *is*
stated in the docs I was reading, it's just in a footnote that I
missed. :-o

Jason