converting an ostream's output to a pure char*

[ravi]

Folks,

I have a heterogenous env. where I developed some C++ code. This code
has the '<<' operator overloaded
to pretty print classes.
This set of classes are instantiated in code which has a constraint on
how to print msgs. (the msgs go to
stdout as well as one or more log files etc. and is controlled by
other factors like brevity of logs etc. Let us
call this function printLog(arg, "format", ...);

What I would ideally like is...
replace 'cout' with 'xout'.
Use xout as always xout << pobj << pobj2 << endl;
Some how get access (readonly is fine) to the formatted string
const char* p = xout.getString() (???)
printLog (args, "%s", p);

Question is how to extract the formatted string from a stream object.

Any help appreciated.

-ravi

[AnonMail2005]

On Jul 17, 1:44*pm, ravi <[e-mail]:

Folks,

I have a heterogenous env. where I developed some C++ code. This code
has the '<<' operator overloaded
to pretty print classes.
This set of classes are instantiated in code which has a constraint on
how to print msgs. (the msgs go to
stdout as well as one or more log files etc. and is controlled by
other factors like brevity of logs etc. Let us
call this function printLog(arg, "format", ...);

What I would ideally like is...
replace 'cout' with 'xout'.
Use xout as always xout << pobj << pobj2 << endl;
Some how get access (readonly is fine) to the formatted string
const char* p = xout.getString() (???)
printLog (args, "%s", p);

Question is how to extract the formatted string from a stream object.

Any help appreciated.

-ravi

Your xout looks like alot like a std::ostringstream (or some object
that contains one). You can get a std::string from that, as well as a
char *. Then you can output it to as many places as you want - cout,
log files, etc.