generating variable

[sagnik`]

this may sound like a stupid question though, but i am having some problem in designing the code for it.

Let us assume that we are calling a function with an arguement which is an integer corresponding to number of variables we need to generate, ie, we have to generate any number of variables dynamically. is there any method of doing this?

Thanx in advance

[sicarie]

Put it in a loop where it creates an array of size (whatever you passed) and it loops that many times, each time calling your variable generator (or rand, or however you are doing it), then return the array.

[ashitpro]

this may sound like a stupid question though, but i am having some problem in designing the code for it.

Let us assume that we are calling a function with an arguement which is an integer corresponding to number of variables we need to generate, ie, we have to generate any number of variables dynamically. is there any method of doing this?

Thanx in advance

"Generating Variable" this term does not sounds good.
You can define the array dynamically

void allocate(int num)
{
   //suppose you are GENERATING(in your language) integer variables.
   int * iArray;
   iArray = (int *)malloc(sizeof(int)*num);
   //here you can use iArray as a vector of variables; 
 
}
 

[sicarie]

"Generating Variable" this term does not sounds good.
You can define the array dynamically

void allocate(int num)
{
   //suppose you are GENERATING(in your language) integer variables.
   int * iArray;
   iArray = (int *)malloc(sizeof(int)*num);
   //here you can use iArray as a vector of variables; 
 
}
 

And your approach will differ depending what language you are using - C or C++.

[sagnik`]

Thank you very much. But actually i was already thinking on that array implementation, i mean, dynamically allocation array with the help of malloc. But is there any way to do the "variable generation" without using the array concept?

I hope malloc can be used in this case also. But i am stuck at the point where i have to declare the same number of int pointer corresponding to the value of the argument passed.

Nevertheless, the discussion helped me. Thanks again.