Help splitting a simple date string

[yogi_bear_79]

I have a simple string (i.e. February 27, 2008) that I need to split
into three parts. The month, day, and year. Splitting into a string
array would work, and I could convert day and years to integers
later. I've bene looking around, and everything I see seems more
complicated than it should be! Help!

[Daniel T.]

On Mar 3, 8:49*pm, yogi_bear_79 <[e-mail]:

I have a simple string (i.e. February 27, 2008) that I need to split
into three parts. The month, day, and year. *Splitting into a string
array would work, and I could convert day and years to integers
later. *I've bene looking around, and everything I see seems more
complicated than it should be! Help!

If you know the format is exactly as you show above, then it is a
simple matter of finding the spaces.

vector<stringsplitDate( const string& str ) {
vector<stringresult;
string::size_type i = str.find( ' ' );
result.push_back( str.substr( 0, i ) );
string::size_type last = i;
i = str.find( ' ', i + 1 );
result.push_back( str.substr( last, i - last ) );
result.push_back( str.substr( i ) );
return result;
}

If you turn the above into your teacher though, he should grade you
very poorly. You really should have some error checking and probably
some sort of verification code.

But the above should at least get you started.

[yogi_bear_79]

On Mar 3, 9:08*pm, "Daniel T." <[e-mail]:

On Mar 3, 8:49*pm, yogi_bear_79 <[e-mail]:

I have a simple string (i.e. February 27, 2008) that I need to split
into three parts. The month, day, and year. *Splitting into a string
array would work, and I could convert day and years to integers
later. *I've bene looking around, and everything I see seems more
complicated than it should be! Help!

If you know the format is exactly as you show above, then it is a
simple matter of finding the spaces.

* *vector<stringsplitDate( const string& str ) {
* * * vector<stringresult;
* * * string::size_type i = str.find( ' ' );
* * * result.push_back( str.substr( 0, i ) );
* * * string::size_type last = i;
* * * i = str.find( ' ', i + 1 );
* * * result.push_back( str.substr( last, i - last ) );
* * * result.push_back( str.substr( i ) );
* * * return result;
* *}

If you turn the above into your teacher though, he should grade you
very poorly. You really should have some error checking and probably
some sort of verification code.

But the above should at least get you started.

Thank you so much for the idea. I do believe that it is slightly more
advanced than I shoul dbe at this point. I've settled on the code
below, just as soon as I parrse out the comma!

char longDate[100];
char* nextToken;

cout << " \n Enter a date in the following format(February 27,
2008):";
cin.getline(longDate,100);

char *month = strtok_s(longDate, " ", &nextToken);
char *day = strtok_s(NULL, ",", &nextToken);
char *year = strtok_s(NULL, "\0", &nextToken);

[Daniel T.]

On Mar 3, 9:53*pm, yogi_bear_79 <[e-mail]:

On Mar 3, 9:08*pm, "Daniel T." <[e-mail]:

On Mar 3, 8:49*pm, yogi_bear_79 <[e-mail]:

I have a simple string (i.e. February 27, 2008) that I need to split
into three parts. The month, day, and year. *Splitting into a string
array would work, and I could convert day and years to integers
later. *I've bene looking around, and everything I see seems more
complicated than it should be! Help!

If you know the format is exactly as you show above, then it is a
simple matter of finding the spaces.

* *vector<stringsplitDate( const string& str ) {
* * * vector<stringresult;
* * * string::size_type i = str.find( ' ' );
* * * result.push_back( str.substr( 0, i ) );
* * * string::size_type last = i;
* * * i = str.find( ' ', i + 1 );
* * * result.push_back( str.substr( last, i - last ) );
* * * result.push_back( str.substr( i ) );
* * * return result;
* *}

If you turn the above into your teacher though, he should grade you
very poorly. You really should have some error checking and probably
some sort of verification code.

But the above should at least get you started.

Thank you so much for the idea. I do believe that it is slightly more
advanced than I shoul dbe at this point. I've settled on the code
below, just as soon as I parrse out the comma!

* * * * char longDate[100];
* * * * char* nextToken;

* * * * cout << " \n Enter a date in the following format(February27,
2008):";
* * * * cin.getline(longDate,100);

* * * * char *month = strtok_s(longDate, " ", &nextToken);
* * * * char *day = strtok_s(NULL, ",", &nextToken);
* * * * char *year = strtok_s(NULL, "\0", &nextToken);- Hide quoted text -

}

The code you show above is considered much more advanced than what I
showed...

[David Harmon]

On Mon, 3 Mar 2008 17:49:40 -0800 (PST) in comp.lang.c++,
yogi_bear_79 <yo**********@yahoo.comwrote,

>I have a simple string (i.e. February 27, 2008) that I need to split
into three parts. The month, day, and year.

My version:
http://groups.google.com/gr*********....earthlink.net