Dimension of array

[Azaz ul haq]

What is meant by dimension of an array?

(Azaz)

[Meetee]

What is meant by dimension of an array?

(Azaz)

Array can be of different dimentions like
a b c d -> 1 dimentional
or
| a b | -> 2 dimentional
| c d |
or
| a b c|
| d e f | -> 3 dimentional
| g h i |

Read more on arrays from google!

[Savage]

Array can be of different dimentions like
a b c d -> 1 dimentional
or
| a b | -> 2 dimentional
| c d |
or
| a b c|
| d e f | -> 3 dimentional
| g h i |

Read more on arrays from google!

The third one is also 2d array,it's a[3][3].

3D array would be array of 2D arrays:(e.g)

|a1 b1| | a2 b2| |. .| ......
|c1 d1| | c2 d2| |. .| ......

Savage

[Spippo]

Yes, Savage, you are right.
In the above example, there are 2 2D arrays.

You can also have arrays with 4 or more dimensions. But you better not use them, because it's hard to visualise how they work.
In most cases a 3D array is hard, so you better stick with 1D or 2D arrays.

You can see an array as a list of elements. If you just have 1 element (for example an integer), you can create it as follow:

int a = 5;
int b = 6;
int c = 12045;

In some cases you don't want a new variable for each element (number), so you create an array of integers. This is just a list of integers:

int d[3] = {5, 6, 12045};

In this example, you create a 1D array (because you specify just one size of the array) which contains 3 elements.

To create a 2D or more dimensional array, you have to specify more sizes of the array. A 2D array can best be visualized as a table, with rows and columns:

int e[4][3];

You can look at this array as it's a table with 4 rows and 3 columns.

3D arrays are like cubes, and need 3 sizes:

int f[3][4][5]

When you want to create a more dimensional array, you need to specify more size. But it's hard to visualize such a array.

[weaknessforcats]

The dimension of an array is the number of elements in the array.

Read this:

First, there are only one-dimensional arrays in C or C++. The number of elements in put between brackets:

int array[5];
 

That is an array of 5 elements each of which is an int.

int array[];
 

won't compile. You need to declare the number of elements.

Second, this array:

int array[5][10];
 

is still an array of 5 elements. Each element is an array of 10 int.

int array[5][10][15];
 

is still an array of 5 elements. Each element is an array of 10 elements where each element is an array of 15 int.

int array[][10];
 

won't compile. You need to declare the number of elements.

Third, the name of an array is the address of element 0

int array[5];
 

Here array is the address of array[0]. Since array[0] is an int, array is the address of an int. You can assign the name array to an int*.

int array[5][10];
 

Here array is the address of array[0]. Since array[0] is an array of 10 int, array is the address of an array of 10 int. You can assign the name array to a pointer to an array of 10 int:

int array[5][10];
 
int (*ptr)[10] = array;
 

Fourth, when the number of elements is not known at compile time, you create the array dynamically:

int* array = new int[value];
int (*ptr)[10] = new int[value][10];
int (*ptr)[10][15] = new int[value][10][15];
 

In each case value is the number of elements. Any other brackets only describe the elements.

Using an int** for an array of arrays is incorrect and produces wrong answers using pointer arithmetic. The compiler knows this so it won't compile this code:

int** ptr = new int[value][10];    //ERROR
 

new returns the address of an array of 10 int and that isn't the same as an int**.

Likewise:

int*** ptr = new int[value][10][15];    //ERROR
 

new returns the address of an array of 10 elements where each element is an array of 15 int and that isn't the same as an int***.

With the above in mind this array:

int array[10] = {0,1,2,3,4,5,6,7,8,9};
 

has a memory layout of

0 1 2 3 4 5 6 7 8 9

Wheras this array:

int array[5][2] = {0,1,2,3,4,5,6,7,8,9};
 

has a memory layout of

0 1 2 3 4 5 6 7 8 9

Kinda the same, right?

So if your disc file contains

0 1 2 3 4 5 6 7 8 9

Does it make a difference wheher you read into a one-dimensional array or a two-dimensional array? No.

Therefore, when you do your read use the address of array[0][0] and read as though you have a
one-dimensional array and the values will be in the correct locations.