How to count Number of Instructions executed in One Second

co*******@gmail.com wrote:

Hi all

I need to get a count the no of instructions [ even assembly language
instructions ] executed in a for loop in exactly one second...
Can any one please give me the code for this...

THANKS IN ADVANCE

One method would be:

1) Count the number of instructions in your loop by getting
an assembly listing from the C compiler.
2) Run the loop for 100 seconds.

3) Divide.

4) Done.

--
jacob navia
jacob at jacob point remcomp point fr
logiciels/informatique
http://www.cs.virginia.edu/~lcc-win32

Nov 10 '07 #4

jacob navia wrote:

2) Run the loop for 100 seconds.

3) Divide.

Well, that should be actually

Run the loop 100 times!

Sorry

--
jacob navia
jacob at jacob point remcomp point fr
logiciels/informatique
http://www.cs.virginia.edu/~lcc-win32

Nov 10 '07 #5

Johannes Bauer

jacob navia schrieb:

One method would be:

1) Count the number of instructions in your loop by getting
an assembly listing from the C compiler.

This is with high likelyhood not the actual number of executed
instructions, as on any modern operating system the sleeping process
will be preempted and instructions will be executed by the
scheduler/operating system/other tasks.

It would be the correct count if the process had exclusive access to the
CPU.

In any case, the problem is poorly specified.

Greetings,
Johannes

--
"PS: Ein Realname wÃ¤re nett. Ich selbst nutze nur keinen, weil mich die
meisten hier bereits mit Namen kennen." -- Markus Gronotte aka "Makus"
aka "Kosst Amojan" aka "maqqusz" in de.sci.electronics
<45**********************@newsspool3.arcor-online.net>

Nov 10 '07 #6

Johannes Bauer wrote:

jacob navia schrieb:

>One method would be:

1) Count the number of instructions in your loop by getting
an assembly listing from the C compiler.

This is with high likelyhood not the actual number of executed
instructions, as on any modern operating system the sleeping process
will be preempted and instructions will be executed by the
scheduler/operating system/other tasks.

It would be the correct count if the process had exclusive access to the
CPU.

In any case, the problem is poorly specified.

Greetings,
Johannes

Obvious. But I thought that the answer referred to the number
of assembly instructions executed by the program...

If the loop is short, the machine is lightly loaded, running 100
loop executions could get below the task time slot and be
executed without any task switch, but that is pure speculation.

You are right that the problem is poorly specified.
--
jacob navia
jacob at jacob point remcomp point fr
logiciels/informatique
http://www.cs.virginia.edu/~lcc-win32

Nov 10 '07 #7

coaassign

On Nov 11, 12:12 am, "coaass...@gmail.com" <coaass...@gmail.com>
wrote:

Hi all

I need to get a count the no of instructions [ even assembly language
instructions ] executed in a for loop in exactly one second...
Can any one please give me the code for this...

THANKS IN ADVANCE

THE ACTUAL PROBLEM IS AS FOLLOWS.....

Write a program (AND/OR manipulate) existing DOS program so as to
count the number of

instructions executed by the p4 processor in the IBM thinkcenter
PC .You can

show any instruction mix executed . Count the exact number of each
distinct

instruction in the total mix executed in one second .After
demonstrating the setup &

the count explain the counts thoroughly....

THE ASSEMBLY INSTRUCTION MIX CAN BE ANYTHING....

Nov 11 '07 #8

How to count number of rows

co*******@gmail.com wrote:

On Nov 11, 12:12 am, "coaass...@gmail.com" <coaass...@gmail.com>
wrote:
>Hi all

I need to get a count the no of instructions [ even assembly language
instructions ] executed in a for loop in exactly one second...
Can any one please give me the code for this...

THANKS IN ADVANCE

THE ACTUAL PROBLEM IS AS FOLLOWS.....

Write a program (AND/OR manipulate) existing DOS program so as to
count the number of

instructions executed by the p4 processor in the IBM thinkcenter
PC .You can

show any instruction mix executed . Count the exact number of each
distinct

instruction in the total mix executed in one second .After
demonstrating the setup &

the count explain the counts thoroughly....

THE ASSEMBLY INSTRUCTION MIX CAN BE ANYTHING....

I am sorry I told you anything. You should do your own homework!
The purpose of homework is to make you learn the issues discussed
in the lessons. If you cheat, you do not learn anything.

Do not cheat.
--
jacob navia
jacob at jacob point remcomp point fr
logiciels/informatique
http://www.cs.virginia.edu/~lcc-win32

Nov 11 '07 #9

Keith Thompson

"co*******@gmail.com" <co*******@gmail.comwrites:

On Nov 11, 12:12 am, "coaass...@gmail.com" <coaass...@gmail.com>
wrote:
>I need to get a count the no of instructions [ even assembly language
instructions ] executed in a for loop in exactly one second...
Can any one please give me the code for this...

THANKS IN ADVANCE

THE ACTUAL PROBLEM IS AS FOLLOWS.....

Write a program (AND/OR manipulate) existing DOS program so as to
count the number of

instructions executed by the p4 processor in the IBM thinkcenter
PC .You can

show any instruction mix executed . Count the exact number of each
distinct

instruction in the total mix executed in one second .After
demonstrating the setup &

the count explain the counts thoroughly....

THE ASSEMBLY INSTRUCTION MIX CAN BE ANYTHING....

THE ACTUAL ANSWER IS AS FOLLOWS.....

Do your own homework.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
Looking for software development work in the San Diego area.
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"

Nov 11 '07 #10

Johannes Bauer

jacob navia schrieb:

I am sorry I told you anything. You should do your own homework!

Totally seconded.

Greetings,
Johannes

--
"PS: Ein Realname wÃ¤re nett. Ich selbst nutze nur keinen, weil mich die
meisten hier bereits mit Namen kennen." -- Markus Gronotte aka "Makus"
aka "Kosst Amojan" aka "maqqusz" in de.sci.electronics
<45**********************@newsspool3.arcor-online.net>

Nov 11 '07 #11

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