implicit constructor

[Rahul]

Hi Everyone,

I know that implicit conversion is invoked for the following case,

class A
{
public: A(int n)
{
...
}
};
A obj = 2;

But is any temp objects created? Is the 2 used to create a temp
object and then is the temp object assigned to the the actual object
obj?

Thanks in advance!!!

[Victor Bazarov]

Rahul wrote:

Hi Everyone,

I know that implicit conversion is invoked for the following case,

class A
{
public: A(int n)
{
...
}
};
A obj = 2;

But is any temp objects created? Is the 2 used to create a temp
object and then is the temp object assigned to the the actual object
obj?

The semantics are such that a temporary object is created. However,
the Standard allows the compiler to forgo creation of a temporary in
such case and construct 'obj' as if you wrote

A obj(2);

The copy-constructor in 'A' has to still be accessible, though.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Rolf Magnus]

Rahul wrote:

Hi Everyone,

I know that implicit conversion is invoked for the following case,

class A
{
public: A(int n)
{
...
}
};
A obj = 2;

But is any temp objects created? Is the 2 used to create a temp
object and then is the temp object assigned to the the actual object
obj?

It's not assigned, but rather copy-constructed. Apart from that, see
Victor's answer.