Table Random

[nurulshidanoni]

Dear all,

Given a table 3 | 2 | 1 | 3 | 2 | 4 |
6 | 9 | 7 | 24 | 5 | 7 |
11 | 28 | 17 | 81 | 10 | 12 |
18 | 65 | 31 | 192 | 17 | 19 |
27 | 126 | 49 | 375 | 26 | 28 |

How to choose a random number from the table using c++?

[Studlyami]

i would put that table into an array and then determine a random number between 0 and the size of the array.

[nurulshidanoni]

how to make into array?

i would put that table into an array and then determine a random number between 0 and the size of the array.

[Ganon11]

Where is this table stored? In a file? Is it already in a 2D array given to you? Is it to be read from input?

[nurulshidanoni]

Like below, how to choose random nums?one only.

#include <iostream>
#include <time.h>
#include <stdio.h>
#include <math.h>
#include <stdlib.h> 
using namespace std;
 
  int main()
{
     int i;
     int nums[66];
 
 
     nums[11]=3;
     nums[12]=6;
     nums[13]=11;
     nums[14]=18;
     nums[15]=27;
     nums[16]=38;
     nums[21]=6;
     nums[22]=9;
     nums[23]=28;
     nums[24]=65; 
     nums[25]=126;
     nums[26]=217; 
     nums[31]=1;
     nums[32]=7; 
     nums[33]=17;
     nums[34]=31; 
     nums[35]=49; 
     nums[36]=71;
     nums[41]=3;
     nums[42]=24;
     nums[43]=81; 
     nums[45]=375;
     nums[44]=192;
     nums[46]=648;
     nums[51]=2;
     nums[52]=52;
     nums[53]=10; 
     nums[54]=17; 
     nums[55]=26; 
     nums[56]=37;
     nums[61]=4;
     nums[62]=7; 
     nums[63]=12; 
     nums[64]=19;
     nums[65]=28;
     nums[66]=39;
 
//choose the random number from data array
    printf("Choose Random Number From Nums\n");

Where is this table stored? In a file? Is it already in a 2D array given to you? Is it to be read from input?

[kaioshin00]

Here's a link to the rand function documentation

See if you can understand how it works and try to come up with generating a random number that will index properly into your array.

Notice the valid indices into your array are 11-16, 21-26, 31-36, 41-46, etc..

[nurulshidanoni]

When i have get the random number is 52, then how can i get the value?

I want like this,nums[52]=52;


#include <iostream>
#include <time.h>
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
using namespace std;

int main()
{

int nums[66];


nums[11]=3;
nums[12]=6;
nums[13]=11;
nums[14]=18;
nums[15]=27;
nums[16]=38;
nums[21]=6;
nums[22]=9;
nums[23]=28;
nums[24]=65;
nums[25]=126;
nums[26]=217;
nums[31]=1;
nums[32]=7;
nums[33]=17;
nums[34]=31;
nums[35]=49;
nums[36]=71;
nums[41]=3;
nums[42]=24;
nums[43]=81;
nums[45]=375;
nums[44]=192;
nums[46]=648;
nums[51]=2;
nums[52]=52;
nums[53]=10;
nums[54]=17;
nums[55]=26;
nums[56]=37;
nums[61]=4;
nums[62]=7;
nums[63]=12;
nums[64]=19;
nums[65]=28;
nums[66]=39;

//choose the random number from data array

printf ("Random initial solution: %d\n", rand() % 55+11);
printf("rand () % 55+1=nums[i] ");
srand ( 1 );


return 0;
}

[kaioshin00]

Remember, your valid indices are 11-16, 21-26, 31-36, 41-46, 51-56, and 61-66

You need to generate a random number that fits in one of these intervals

There might be several ways to do this, one is as follows:

Create a random number.
Mod it by 6, and then add 1.

This will either give you 1, 2, 3, 4, 5, or 6

Take this new number and multiply it by 10.

This will give you 10, 20, 30, 40, 50, or 60.

Crate a new random number.
Mod it by 7
This new random number will either be 0, 1, 2, 3, 4, 5, or 6
Add this new number to the previous number, which was either 10, 20, 30, 40, 50, or 60

This will give you a random index into your array.

Let me know if any of that isn't clear.

[nurulshidanoni]

Thak you for reply my forum. i have get the random number like [52], but i want the value also.How to call the value?

Remember, your valid indices are 11-16, 21-26, 31-36, 41-46, 51-56, and 61-66

You need to generate a random number that fits in one of these intervals

There might be several ways to do this, one is as follows:

Create a random number.
Mod it by 6, and then add 1.

This will either give you 1, 2, 3, 4, 5, or 6

Take this new number and multiply it by 10.

This will give you 10, 20, 30, 40, 50, or 60.

Crate a new random number.
Mod it by 7
This new random number will either be 0, 1, 2, 3, 4, 5, or 6
Add this new number to the previous number, which was either 10, 20, 30, 40, 50, or 60

This will give you a random index into your array.

Let me know if any of that isn't clear.

[nurulshidanoni]

#include <iostream>
#include <time.h>
#include <stdio.h>
#include <math.h>
#include <stdlib.h> 
#define WIDTH 7
#define HEIGHT 7
 {   
    int main()
    int i, j;
    int [i][j]=[6][6];
    [i][j]=(2+pow(x[i],2));
    [i][j]=(1+pow(x[i],3));
    [i][j]=(2*pow(x[i],2)-1);
    [i][j]=(3*pow(x[i],3));
    [i][j]=(1+pow(x[i],2));
    [i][j]=(3+pow(x[i],2));
 
{
    for (i=0;j<HEIGHT;i++)
    for (j=0;j<WIDTH;j++)
 
} 
    printf("\n Data for Cost Function and Quantity of Resource Allotted\n");
{
    for(i=1; i<=6; i++)
    for(j=1; j<=6; j++)
 
    [i][j]=[6][6];
    [i][j]=(2+pow(x[i],2));
    [i][j]=(1+pow(x[i],3));
    [i][j]=(2*pow(x[i],2)-1);
    [i][j]=(3*pow(x[i],3));
    [i][j]=(1+pow(x[i],2));
    [i][j]=(3+pow(x[i],2));
 
}   printf("\n");
    for(i=1; i<=6; i++)
    for(j=1; j<=6; j++)
{
 
    printf  ("i\t [i][j]\t [i][j]\t [i][j]\t [i][j]\t\ [i][j]\t [i][j]\n");
    printf  ("-\t -\t -\t -\t -\t -\t -\t\n");     
 
{
    for(i=1; i<=6; i++)
    for(j=1; j<=6; j++)
    printf("%d\t %d\t %d\t %d\t %d\t %d\t %d\n", i, [i][j],  [i][j], [i][j], [i][j], [i][j], [i][j]);
 
}
 
//choose the random number from data array
 
    printf ("Random initial solution: %d\n", rand() % 6);
 
    srand ( 1 );
 
 
    return 0;
}
 
}  }

[hariharanmca]

Do not simply post code.
Explain your problem detail.

[Savage]

Thak you for reply my forum. i have get the random number like [52], but i want the value also.How to call the value?

how about:

a[52/*or any other number you get*/]

,regards

Savage

[sicarie]

nurulshidanoni-

Please confine your questions on the same topic to a single thread.