My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
Thanks in advance.
10  2802 
Pardon me.What about only the values 0 to 255,with 255 being 1111 1111?
In article <11**********************@g4g2000hsf.googlegroups. com>, zg******@gmail.com says...
Pardon me.What about only the values 0 to 255,with 255 being 1111 1111?
The obvious way would be to create an array (or vector) or strings, one
for each possible value of a nybble (16 possible values). Use the type
four bits as an index, print out the chosen string, print a space, then
print out the string indexed with the bottom four bits.
--
Later,
Jerry.
The universe is a figment of its own imagination. zg******@gmail.com wrote:
My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
Thanks in advance.
if you use recursive way, then you have no idea how long is the binary
number, so it's impossible to print the space character.
so you have to borrow extra storage and traverse the storage from end to
begin like Jerry mentioned else thread.
--
Thanks
Barry
On Wed, 12 Sep 2007 18:44:00 -0700, zg******@gmail.com wrote:
>My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
You may use std::bitset to store the number, and use to_string member
function.
#include <string>
#include <bitset>
#include <iostream>
int main()
{
std::bitset<8number(145);
std::string representation(number.to_string());
std::cout
<<representation.substr(0,4)<<' '
<<representation.substr(4)<<std::endl;
}
Best regards,
Zara
Zara wrote:
On Wed, 12 Sep 2007 18:44:00 -0700, zg******@gmail.com wrote:
>My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
You may use std::bitset to store the number, and use to_string member
function.
#include <string>
#include <bitset>
#include <iostream>
int main()
{
std::bitset<8number(145);
std::string representation(number.to_string());
std::cout
<<representation.substr(0,4)<<' '
<<representation.substr(4)<<std::endl;
}
using bitset and its to_string()
in this way, you have to ignore all the heading '0's
--
Thanks
Barry
<zg******@gmail.comwrote in message
news:11**********************@k79g2000hse.googlegr oups.com...
My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
Thanks in advance.
Many ways, depending on how you are outputing the binary value. It may be
as simple as putting in a << " " << somewhere
Show us how you are currently outputting/formatting your output.
On Thu, 13 Sep 2007 16:10:48 +0800, Barry <dh*****@gmail.comwrote:
>Zara wrote:
>On Wed, 12 Sep 2007 18:44:00 -0700, zg******@gmail.com wrote:
>>My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
You may use std::bitset to store the number, and use to_string member
function.
#include <string>
#include <bitset>
#include <iostream>
int main()
{
std::bitset<8number(145);
std::string representation(number.to_string());
std::cout
<<representation.substr(0,4)<<' '
<<representation.substr(4)<<std::endl;
}
using bitset and its to_string()
in this way, you have to ignore all the heading '0's
No, because t to_string generates exactly eisht characters, as
requested by OP
On Sep 13, 3:44 am, zgfar...@gmail.com wrote:
My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
See my response in the other thread you started ("Conversions
from decimal to binary,hex"). There are several different
solutions.
--
James Kanze (GABI Software) email:ja*********@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
9 place Sémard, 78210 St.-Cyr-l'École, France, +33 (0)1 30 23 00 34
Zara wrote:
On Thu, 13 Sep 2007 16:10:48 +0800, Barry <dh*****@gmail.comwrote:
>Zara wrote:
>>On Wed, 12 Sep 2007 18:44:00 -0700, zg******@gmail.com wrote:
My program converts decimals to binary, hex etc. The output of the
binary numbers are to be in the form 0000 0000 for all numbers from 0
to 300. Does anyone have any suggestions as how to get the space
between each 4 bits?
You may use std::bitset to store the number, and use to_string member
function.
#include <string>
#include <bitset>
#include <iostream>
int main()
{
std::bitset<8number(145);
std::string representation(number.to_string());
std::cout
<<representation.substr(0,4)<<' '
<<representation.substr(4)<<std::endl;
}
using bitset and its to_string()
in this way, you have to ignore all the heading '0's
No, because t to_string generates exactly eisht characters, as
requested by OP
Well,
if "0011 1100" is OK, then OK
I thought for a binary number it would prettier to write "11 1100"
--
Thanks
Barry This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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