Is struct() equivalent to ZeroMemory() ?

[Jim Langston]

For some code I copied off of MSDN it uses the Cism of

OPENFILENAME ofn;
ZeroMemory(&ofn, sizeof(ofn));

I was wondering if
OPENFILENAME ofn = OPENFILENAME();
is equivalent for all cases of a structure?

Would this also asign pointers a value of NULL (which this structure does
use, pointers).

Or should I just stick with the Cism of ZeroMemory for a structure that can
be used in C and C++

[Old Wolf]

On Aug 25, 2:38 pm, "Jim Langston" <[e-mail]:

OPENFILENAME ofn = {sizeof(OPENFILENAME}};

although I think some people would use

OPENFILENAME ofn = {sizeof(ofn)};

Not sure which is prefered, but I generally use the
class/structure name in sizeof instead of an instance.

I can't think of any rational reason why you would use the
former. Can you enlighten me?

[Jim Langston]

"Old Wolf" <ol*****@inspire.net.nzwrote in message
news:11**********************@q4g2000prc.googlegro ups.com...

On Aug 25, 2:38 pm, "Jim Langston" <[e-mail]:

> OPENFILENAME ofn = {sizeof(OPENFILENAME}};

although I think some people would use

OPENFILENAME ofn = {sizeof(ofn)};

Not sure which is prefered, but I generally use the
class/structure name in sizeof instead of an instance.

I can't think of any rational reason why you would use the
former. Can you enlighten me?

You can't think of any rational reason to use the sizeof the class, or the
sizeof the instance?