About C++ Reference

[and.280.c]

hello m newbie at here now i have a problem with the "Reference" in "C+
+". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5; ri =10;
std::cout << i << " " << ri << std::endl;
}
and the compiler return the answer 10 10
can there anyone who can tell me about it
how compiler take the value and return it
Andry

[Jim Langston]

<an*******@gmail.comwrote in message
news:11*********************@j4g2000prf.googlegrou ps.com...

hello m newbie at here now i have a problem with the "Reference" in "C+
+". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5; ri =10;
std::cout << i << " " << ri << std::endl;
}
and the compiler return the answer 10 10
can there anyone who can tell me about it
how compiler take the value and return it
Andry

To format your program a little better (IMO)

#include<iostream>
int main()
{
int i;
// i is now an integer
int &ri = i;
// ri is a reference to an integer, in this case i. Whenever we deal
with ri
// it is just as if we are dealing with the orignal variable i
i = 5;
// That assigned the value of i to 5
ri =10;
// That assigned the value of i (which ri is a reference to) to 10.
std::cout << i << " " << ri << std::endl;
// i and ri both refer to the same variable i, which has 10 in it.
}

[David Harmon]

On Fri, 27 Jul 2007 22:52:56 -0700 in comp.lang.c++, an*******@gmail.com
wrote,

>hello m newbie at here now i have a problem with the "Reference" in "C+
+". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5; ri =10;
std::cout << i << " " << ri << std::endl;
}

int &ri = i; // means that ri is another name for variable i.

[Default User]

an*******@gmail.com wrote:

hello m newbie at here now i have a problem with the "Reference" in
"C+ +". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5; ri =10;
std::cout << i << " " << ri << std::endl;
}
and the compiler return the answer 10 10
can there anyone who can tell me about it
how compiler take the value and return it
Andry

A reference creates an alias for the assigned variable. Your code was
effectively:

i = 5;
i =10;

std::cout << i << " " << i << std::endl;
See now?

Brian

[Tak]

On Jul 28, 1:52 pm, [e-mail] wrote:

hello m newbie at here now i have a problem with the "Reference" in "C+
+". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5;

i=5 ri=5

ri =10;

i=10,ri=10

std::cout << i << " " << ri << std::endl;

}

[and.280.c]

On Jul 28, 12:07 am, "Jim Langston" <[e-mail]:

<[e-mail] in message

news:11*********************@j4g2000prf.googlegrou ps.com...

hello m newbie at here now i have a problem with the "Reference" in "C+
+". i am following the Book("C++ Primer,Fourth Edition")
there is The Question

#include<iostream>
int main()
{
int i, &ri = i;
i = 5; ri =10;
std::cout << i << " " << ri << std::endl;
}

and the compiler return the answer 10 10
can there anyone who can tell me about it
how compiler take the value and return it
Andry

To format your program a little better (IMO)

#include<iostream>
int main()
{
int i;
// i is now an integer
int &ri = i;
// ri is a reference to an integer, in this case i. Whenever we deal
with ri
// it is just as if we are dealing with the orignal variable i
i = 5;
// That assigned the value of i to 5
ri =10;
// That assigned the value of i (which ri is a reference to) to 10.
std::cout << i << " " << ri << std::endl;
// i and ri both refer to the same variable i, which has 10 in it.

}

thanks a lot for this