Why does this return fail to work while the other doesn't?

[The Cool Giraffe]

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

Of course i have that char ch[10] and i'm returning
std:string from the method. I'm using VC++.NET compiler.

--
Vänligen Kerstin Viltersten
(The Cool Giraffe)

[Victor Bazarov]

The Cool Giraffe wrote:

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

Because you're trying to declare an object (named 'outPut') in
the return statement's expression. That is not allowed. You
need:

return std::string(ch);

which just creates a temporary [unnamed] object of type string
and returns its value.

Of course i have that char ch[10] and i'm returning
std:string from the method. I'm using VC++.NET compiler.

Compiler doesn't matter.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Thomas Tutone]

On Feb 13, 11:17 am, "The Cool Giraffe" <[e-mail]>
wrote:

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

change that to:

return std::string(ch);

and all should be good.

Best regards,

Tom

[Rolf Magnus]

The Cool Giraffe wrote:

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

It just said "no"? That's quite a useless error message.

return (std::string outPut (ch));

A variable definition has no value. You have to use a temporary:

return std::string(ch);

[David Harmon]

On Tue, 13 Feb 2007 17:17:59 +0100 in comp.lang.c++, "The Cool Giraffe"
<gi******@viltersten.comwrote,

>Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

What is "output" doing there? You can't declare a variable just in the
middle of an expression.

return std::string(ch);

[The Cool Giraffe]

Thomas Tutone wrote/skrev/kaita/popisal/schreibt :

"The Cool Giraffe" <[e-mail]>

>I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

change that to:

return std::string(ch);

and all should be good.

Best regards,

Got it. Thanks to all.

--
Vänligen Kerstin Viltersten
(The Cool Giraffe)

[Alan Johnson]

Rolf Magnus wrote:

>the computer said no. Why?

It just said "no"? That's quite a useless error message.

I work with an IDL compiler which has only one error message:
"You used it wrong."

--
Alan Johnson