How to get address of templated object?

[Rickarazzi]

This is a problem that arose while using GNU G++ 3.4.5 under Linux.
The problem is: How to get a pointer value from a templated object
inside a class? Normally, I would add an '&' can carry on. This does
not seem to work.

Below is the example I used and some of the things I tried and the gnu
errors I got. There are only two classes, Base and Derived, where
Base defines the buffer, and Derived tries to set a pointer to it.

Is this a gnu g++ issue or is there some syntax I missing?

Rick
template <typename CharT>
class Base
{
public:
CharT buffer_;
};
template <typename CharT>
class Derived: public Base<CharT>
{
public:
Derived( void)
{
CharT * ptr = & buffer_; // error: `buffer_' was not
declared in this scope
CharT * ptr = & Base<CharT>::buffer_; // error: cannot
convert `char Base<char>::*' to `char*' in initialization
CharT * ptr = & (Base<CharT>::buffer_); // error: same as
last one

// This works but sure is ugly
CharT & ref = Base<CharT>::buffer_;
CharT * ptr = & ref;
}
};
int main( void)
{
Derived<chardah;
}

[Kai-Uwe Bux]

Ri********@comcast.net wrote:

template <typename CharT>
class *Base
{
public:
CharT *buffer_;
};
template <typename CharT>
class *Derived: * public Base<CharT>
{
public:
Derived( void)
{
CharT * ptr = *& buffer_; * // error: `buffer_' was not
declared in this scope
CharT * ptr = *& Base<CharT>::buffer_; *// error: cannot
convert `char Base<char>::*' to `char*' in initialization
CharT * ptr = *& (Base<CharT>::buffer_); // error: *same as
last one

// This works but sure is ugly
CharT & ref = *Base<CharT>::buffer_;
CharT * ptr = & ref;

try:

CharT * ptr = & this->buffer_;

}
};
int main( void)
{
Derived<chardah;
}

Best

Kai-Uwe Bux

[Gianni Mariani]

Ri********@comcast.net wrote:

This is a problem that arose while using GNU G++ 3.4.5 under Linux.
The problem is: How to get a pointer value from a templated object
inside a class? Normally, I would add an '&' can carry on. This does
not seem to work.

If the member is in another dependant base class, then the compiler
can't deduce what buffer_ is and so you get an error. Using, this->,
while redundant in non templated classes, tells the compiler that
buffer_ is dependant on the template parameters.

>
Below is the example I used and some of the things I tried and the gnu
errors I got. There are only two classes, Base and Derived, where
Base defines the buffer, and Derived tries to set a pointer to it.

Is this a gnu g++ issue or is there some syntax I missing?

I think g++ is right.

>
Rick
template <typename CharT>
class Base
{
public:
CharT buffer_;
};
template <typename CharT>
class Derived: public Base<CharT>
{
public:
Derived( void)
{

CharT * ptr = & this->buffer_;

CharT * ptr = & buffer_; // error: `buffer_' was not
declared in this scope
CharT * ptr = & Base<CharT>::buffer_; // error: cannot
convert `char Base<char>::*' to `char*' in initialization
CharT * ptr = & (Base<CharT>::buffer_); // error: same as
last one

// This works but sure is ugly
CharT & ref = Base<CharT>::buffer_;
CharT * ptr = & ref;
}
};
int main( void)
{
Derived<chardah;
}

[Grizlyk]

Ri********@comcast.net wrote:

>
template <typename CharT>
class Base
{
public:
CharT buffer_;
};
template <typename CharT>
class Derived: public Base<CharT>
{
public:

using Base<CharT>::buffer_;

http://www.parashift.com/c++-faq-lite/templates.html
[35.19] Why am I getting errors when my template-derived-class uses a member
it inherits from its template-base-class?

Derived( void)
{
CharT * ptr = & buffer_;
// error: `buffer_' was not declared in this scope

--
Maksim A. Polyanin

"In thi world of fairy tales rolls are liked olso"
/Gnume/