How do we write odd function in an if-else statement

[Nhd]

I'm facing some problems.. Its very basic but i cant seems to remember how to go abt doing it...

Im supposed to input in a value
if it is 1, then im supposed to stop the program,
if n is odd, then n=n*3+1,
else n=n/2

What ive written is

int n;

cin>>n;

if (n==1)
{
cout<<n<<endl;
}

else if (n==??) ---> I'm supposed to write this as 'if n is an odd number, answer will be as follows..
{
n = 3*n + 1;
}

else
{
n = n/2;
}

cout<<n<<endl;

I;m not sure how do i do the ODD part.. Can anyone kindly help me in this.. Thank u..

[Ganon11]

If a number is odd, than it is not evenly divisible by 2 - in other words, it will have a remainder of 1. What operator can you use to check the remainder of a number divided by 2?

[Nhd]

If a number is odd, than it is not evenly divisible by 2 - in other words, it will have a remainder of 1. What operator can you use to check the remainder of a number divided by 2?

is the the % operator? meaning i shud juz write it as

if (n%2)
{
n=3*n+1;
}

ok, thk u so much, i get this already... i can go to the second part now... Thanks alot

[shardul316]

for odd number you have to use
if(n%2!=0)
{


n=3*n+1;

}

where n%2!=0 is the condition to check odd number.
for even number it condition will be n%2==0.

[horace1]

for odd number you have to use
if(n%2!=0)
{

n=3*n+1;
}
where n%2!=0 is the condition to check odd number.
for even number it condition will be n%2==0.

either

if(n%2!=0)
 

which is true if the number is odd
or

if(n%2)
 

which is non zero if the number is odd will work because C/C++ treats a non zero value as true

[Nhd]

Thanks shardul316 and horace1..

Ive goten that part right already...

However, may i noe how do we continuously continue this statement. i tried using a for loop, but it doesnt work..

after i input in 22, 11 will be the output that i'll get.. but im expected to get this output instead -> 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1..

which means that the output is continuously fed into the loop till i get 1, then it will terminate. is there anyone who might noe how to go abt starting this...

for eg, 22 is even, hence 22/2 is 11.
11 is odd, then 3*11+1 is 34.
34 is even, 34/2 is 17 and it goes on...

and how do we start counting cycle length?

[horace1]

try

            int n;
            scanf("%d", &n);
            while(n!=1)
            if(n%2) 
               {
                printf("odd %d ", n); 
                n = 3*n + 1; 
               }
            else  
               {
               printf("even %d ", n); 
               n = n/2; 
               }