questions about c

[sagnik]

Hello everybody!! I am new to this forum. i am a student pursuing course in computer in india. Right now I have 3 questions.
1. Files are stored in hdd. then how do we access them using file pointers?
2. why the file pointers are exceptionally written in upper-cases("FILE") ?
3.what result should following code give ?
int i =7;
int j;
j= i++ * i++;
my compiler (TC++ IDE) gives 49. Is it logical? why the increment is not inflicted? Is the result compiler independent?

[sicarie]

Hello everybody!! I am new to this forum. i am a student pursuing course in computer in india. Right now I have 3 questions.
1. Files are stored in hdd. then how do we access them using file pointers?
2. why the file pointers are exceptionally written in upper-cases("FILE") ?
3.what result should following code give ?
int i =7;
int j;
j= i++ * i++;
my compiler (TC++ IDE) gives 49. Is it logical? why the increment is not inflicted? Is the result compiler independent?

1. declare the pointer and open the file.
2. because that's what the programmer typed.
3. try running it twice, then try running it with ++i * ++i twice as well, possibly even with ++i * i++. That should lead you to your answer.

What do you think about the first two?

[Banfa]

3.what result should following code give ?
int i =7;
int j;
j= i++ * i++;
my compiler (TC++ IDE) gives 49. Is it logical? why the increment is not inflicted? Is the result compiler independent?

The result is undefined behaviour because it attempts to modify the vaule of a variable twice between sequence points.

Undefined behaviour is bad and should be avoided, you do not even have any garuntee that the calculation will produce the same result 2 times in a row.

[apv2feb]

Answer for your 3rd question.
in c for increement any no, are two ways
++i and i++
postfix, prefix type
you are using postfix so
the increemnts are done after multiplication.
as example check this

int i=7;
int j;
j=i++*i++;
printf("%d\n",j);
printf("%d",i);


out put is

49
8

okay...........