assign const_iterator to const pointer

[kotau]

Hi,

I'm having trouble with something that would appear to have a simple
solution.

Here's a version of the code I'm working with:
const Item* p 0;
name::const_iterator i;
name:const_iterator e = p1->end();
for (i=p1->begin(); i<e ++i)
{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}

The compiler returns that it "cannot convert from const_iterator to
const(Item*)"
I have spent a few hours looking for a definitive answer and have found
nothing so far.

Any help will be greatly appreciated.

Cheers.

Patrick

[Earl Purple]

kotau wrote:

Hi,

I'm having trouble with something that would appear to have a simple
solution.

Here's a version of the code I'm working with:

const Item* p 0;

What is Item?

name::const_iterator i;

What is name?

name:const_iterator e = p1->end();

Missing a :
What is p1?

for (i=p1->begin(); i<e ++i)

iterators should be compared with operator == and operator !=, not with
operator <

{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}

The compiler returns that it "cannot convert from const_iterator to
const(Item*)"

Because it probably can't and why should it? Iterators do not have to
take assignment to pointers.

I have spent a few hours looking for a definitive answer and have found
nothing so far.

The answer lies not in how you get your iterator to assign to a pointer
but to how to manage to do what you need to do without it.

[kotau]

Hi,

Thanks for your reply. Sorry for the syntax errors above.

Here's a more complete version:

static const Item* somefunc(const name* p1, const char* var)
{

const Item* p = 0;
name::const_iterator i;
name::const_iterator e = p1->end();
for (i=p1->begin(); i<e ++i)
{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}
}
Someone else wrote the code and I'm trying to fix it...

Cheers.

On Nov 9, 6:00 pm, "Earl Purple" <[e-mail]:

kotau wrote:

Hi,

I'm having trouble with something that would appear to have a simple
solution.

Here's a version of the code I'm working with:
const Item* p 0;What is Item?

name::const_iterator i;What is name?

name:const_iterator e = p1->end();Missing a :

What is p1?

for (i=p1->begin(); i<e ++i)iterators should be compared with operator == and operator !=, not with

operator <

{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}

The compiler returns that it "cannot convert from const_iterator to
const(Item*)"Because it probably can't and why should it? Iterators do not have to

take assignment to pointers.

I have spent a few hours looking for a definitive answer and have found
nothing so far.The answer lies not in how you get your iterator to assign to a pointer

but to how to manage to do what you need to do without it.

[Jim Langston]

"kotau" <dj********@gmail.comwrote in message
news:11**********************@h54g2000cwb.googlegr oups.com...

Hi,

Thanks for your reply. Sorry for the syntax errors above.

Here's a more complete version:

static const Item* somefunc(const name* p1, const char* var)
{

const Item* p = 0;
name::const_iterator i;
name::const_iterator e = p1->end();
for (i=p1->begin(); i<e ++i)
{
if (stricmp(i->func(), var) == 0)
{
p = i;

p is an Item*, i is a const_iterator. They are not assignable. The way to
convert an iterator to a pointer is to dereference the iterator, then take
the address of it. Try:
p = &(*i);

break;
}
}
}
Someone else wrote the code and I'm trying to fix it...

Cheers.

On Nov 9, 6:00 pm, "Earl Purple" <[e-mail]:

>kotau wrote:

Hi,

I'm having trouble with something that would appear to have a simple
solution.

Here's a version of the code I'm working with:
const Item* p 0;What is Item?

name::const_iterator i;What is name?

name:const_iterator e = p1->end();Missing a :

What is p1?

for (i=p1->begin(); i<e ++i)iterators should be compared with
operator == and operator !=, not with

operator <

{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}

The compiler returns that it "cannot convert from const_iterator to
const(Item*)"Because it probably can't and why should it? Iterators do
not have to

take assignment to pointers.

I have spent a few hours looking for a definitive answer and have found
nothing so far.The answer lies not in how you get your iterator to
assign to a pointer

but to how to manage to do what you need to do without it.

[kotau]

Thanks that gets the compile working.

This group rocks!!!

Patrick.

On Nov 9, 6:17 pm, "Jim Langston" <[e-mail]:

"kotau" <[e-mail] in messagenews:11**********************@h54g2000cwb.g ooglegroups.com...

Hi,

Thanks for your reply. Sorry for the syntax errors above.

Here's a more complete version:

static const Item* somefunc(const name* p1, const char* var)
{

const Item* p = 0;
name::const_iterator i;
name::const_iterator e = p1->end();
for (i=p1->begin(); i<e ++i)
{
if (stricmp(i->func(), var) == 0)
{
p = i;p is an Item*, i is a const_iterator. They are not assignable. The way to

convert an iterator to a pointer is to dereference the iterator, then take
the address of it. Try:
p = &(*i);

break;
}
}
}

Someone else wrote the code and I'm trying to fix it...

Cheers.

On Nov 9, 6:00 pm, "Earl Purple" <[e-mail]:

kotau wrote:
Hi,

I'm having trouble with something that would appear to have a simple
solution.

Here's a version of the code I'm working with:
const Item* p 0;What is Item?

name::const_iterator i;What is name?

name:const_iterator e = p1->end();Missing a :
What is p1?

for (i=p1->begin(); i<e ++i)iterators should be compared with
operator == and operator !=, not with
operator <

{
if (stricmp(i->func(), var) == 0)
{
p = i;
break;
}
}

The compiler returns that it "cannot convert from const_iterator to
const(Item*)"Because it probably can't and why should it? Iterators do
not have to
take assignment to pointers.

I have spent a few hours looking for a definitive answer and have found
nothing so far.The answer lies not in how you get your iterator to
assign to a pointer
but to how to manage to do what you need to do without it.