7 Hrs Left To Die ! Please Help

[marsguy85]

a program that repeatedly request an integer from the user and displays the integer as a binary number. It should terminate when the value 9999 is entered. A typical run might look like:
Enter integer: 16
00000000000000000000000000010000
Enter integer: -1
11111111111111111111111111111111
Enter integer: 9999
Try various values including negative and check that they are correct – the storage of signed numbers in binary was discussed in the level 1 module Computer Architecture.
You will need to use one of the shift operators (<< or >>) and the bitwise AND operator & (not &&). The basic idea is to AND a mask with the number. To give you an idea of the algorithm, suppose integers are 8 bits long rather than 32 bits and the variable data contains the number and the variable mask the mask.
Number 01110010
Mask 10000000
AND'ed = 10000000

If the result of AND'ing data with mask is non zero print a one else print a 0. Now shift the mask one bit right (>>) and repeat the AND.
number 01110010
mask 01000000
AND'ed = 01000000

Continue until the mask has been shifted eight bits right

ITS IN ANSI C . AND MASK IS MUST.
I HAVE DONE SO FAR THIS BUT CANT FIGURE OUT WHERE AND HOW TO ADD MASK.

 
main()
{
int i,n;
for(;;)
{
printf("\nEnter the number\n");//number to convert
scanf("%d",&n);
if ( n==9999) //condition check
return;
else
{
for(i=0;i<32;i++)
{
printf("%d",(n<<i & 1<<31 )?1:0); //converting to binary
}// for ends
}//else ends
}//for ends
}//main ends
 
 
 

PLEASE HELP ME ASAP AS ONLY 7 HRS LEFT TO SUBMIT THIS . I REALLY NEED THE GRADE OF THIS.HELP

[Banfa]

What are you talking about, apart from the fact that

main()

should be declared

int main(int argc, char **argp)

for ANSI complience and of course since main returns int you should return a value

return 0;

is normal

you have a working program. The mask is incorperated into the printf statement, take a little time to understand how it is working.