Default precision of cout

utab

Dear all,

What is the default precision of cout for double types?(I think that
was 6 if I am not mistaken)

On the same cout statement I got(without any formatting)

0.00245579 0.00246217 80000
------------------------------------------------------
0.43077 0.022031 80000
------------------------------------------------------
0.425618 0.022031 80000
------------------------------------------------------
0.441189 0.022031 80000

The first line has 8 digits precision and the others have 6 or 5.

Regards,

Sep 5 '06 #1

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10220

Clark S. Cox III

utab wrote:

Dear all,

What is the default precision of cout for double types?(I think that
was 6 if I am not mistaken)

On the same cout statement I got(without any formatting)

Where is the code that produced this output?

0.00245579 0.00246217 80000
------------------------------------------------------
0.43077 0.022031 80000
------------------------------------------------------
0.425618 0.022031 80000
------------------------------------------------------
0.441189 0.022031 80000

The first line has 8 digits precision and the others have 6 or 5.

No, the first line still only has 6 significant digits.
--
Clark S. Cox III
cl*******@gmail.com

Sep 5 '06 #2

Victor Bazarov

utab wrote:

What is the default precision of cout for double types?(I think that
was 6 if I am not mistaken)

Yes, 6.

>
On the same cout statement I got(without any formatting)

0.00245579 0.00246217 80000
------------------------------------------------------
0.43077 0.022031 80000
------------------------------------------------------
0.425618 0.022031 80000
------------------------------------------------------
0.441189 0.022031 80000

The first line has 8 digits precision and the others have 6 or 5.

No, all have 6 digits of _precision_. The leading zeros do not count.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

Sep 5 '06 #3

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