int representation incorrect

[Steve]

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
cout << count << endl;
}

I expect just 0..4 to be printed on the following line but I get
1072693249
1072693250
1072693251
1072693252

why would this be happening?

[gangs]

I compiled in the folloiwng environment:
Compiler: mingw
OS: Win 2000 professional

It displayed 0 5 times.

can you tell us a little more about the kind of environment in which
you are compiling?

[kveerarani]

Are you sure you want to print 'count' in the for loop ? You seem to be
expecting 'i'.
I used follg code and it printed 0....4.

#include <iostream>

main ()
{
unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
std::cout << i << std::endl;

}
}

[Jaspreet]

Steve wrote:

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
cout << count << endl;
}

I expect just 0..4 to be printed on the following line but I get
1072693249
1072693250
1072693251
1072693252

why would this be happening?

You shuld be getting 0 displayed 5 times. Try again with the code you
have pasted and let us know what you get as output.

If you want 0 to 4 to be displayed then use "i" in cout.

[Jaspreet]

kv********@gmail.com wrote:

Are you sure you want to print 'count' in the for loop ? You seem to be
expecting 'i'.
I used follg code and it printed 0....4.

#include <iostream>

main ()
main() should return int.
{
unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
std::cout << i << std::endl;

} return 0; }

[Steve]

Steve wrote:

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
cout << count << endl;
}

I expect just 0..4 to be printed on the following line but I get
1072693249
1072693250
1072693251
1072693252

why would this be happening?

Sorry, the code looks more like this. I initialize the count variable
then some other lines of code are executed which do not access or change
the count variable and then the for loop is executed. I had a mistake
before it should have been cout << count++ << endl;

unsigned int count = 0;
.... code that does not directly change count ....
for( int i = 0; i < 5; i++ ){
cout << count++ << endl;
}

[Jaspreet]

Steve wrote:

Steve wrote:

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
cout << count << endl;
}

I expect just 0..4 to be printed on the following line but I get
1072693249
1072693250
1072693251
1072693252

why would this be happening?

Sorry, the code looks more like this. I initialize the count variable
then some other lines of code are executed which do not access or change
the count variable and then the for loop is executed. I had a mistake
before it should have been cout << count++ << endl;

unsigned int count = 0;
... code that does not directly change count ....
for( int i = 0; i < 5; i++ ){
cout << count++ << endl;
}

You again seem to be missing something. If I try your code snippet, I
do get 0-4. Are you sure you are displaying the count variable ? There
might be a typo and you may by mistake be referring to a variable
declared with a similar name (cnt, etc..) which has been declared but
not initalised.

Probably pasting the code would help us all. Sorry cannot be of much
help.

[Kai-Uwe Bux]

Steve wrote:

Steve wrote:

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
cout << count << endl;
}

I expect just 0..4 to be printed on the following line but I get
1072693249
1072693250
1072693251
1072693252

why would this be happening?
Sorry, the code looks more like this. I initialize the count variable
then some other lines of code are executed which do not access or change
the count variable and then the for loop is executed. I had a mistake
before it should have been cout << count++ << endl;

unsigned int count = 0;
... code that does not directly change count ....

And I bet you, this is where your bug is hiding.

Also, if this code does not change count, why do you declare and initialize
count before this point?
for( int i = 0; i < 5; i++ ){
cout << count++ << endl;
}

Best

Kai-Uwe Bux

[asterisc]

Because it's unsigned, maybe if you substract from count, you will get
big values, like:

unsigned int count = 0;
for( int i = 0; i < 5; i++ )
{
cout << --count << endl;
}

=>
4294967295
4294967294
4294967293
4294967292
4294967291

[Ben Pope]

Jaspreet wrote:

kv********@gmail.com wrote:

Are you sure you want to print 'count' in the for loop ? You seem to be
expecting 'i'.
I used follg code and it printed 0....4.

#include <iostream>

main ()

main() should return int.

{
unsigned int count = 0;
for( int i = 0; i < 5; i++ ){
std::cout << i << std::endl;

}

return 0;

// if we're going to be pedantic, then that return
// statement is not required.

}

Ben Pope
--
I'm not just a number. To many, I'm known as a string...

[Ben Pope]

Steve wrote:

I am trying to print a simple int output using a for loop and
incrementing a number along the way such as

Stop posting code that does not demonstrate your problem, it's a waste
of everybodies time.

Write a complete, compilable program, in your favourite editor. Compile
it. If it demonstrates your problem, THEN copy and paste it here.

Only then can we help.

Ben Pope
--
I'm not just a number. To many, I'm known as a string...

[Kai-Uwe Bux]

asterisc wrote:

Because it's unsigned, maybe if you substract from count, you will get
big values, like:

unsigned int count = 0;
for( int i = 0; i < 5; i++ )
{
cout << --count << endl;
}

=>
4294967295
4294967294
4294967293
4294967292
4294967291

Did you really mean that as a reply to *my* post?

Well, one cannot tell since you didn't bother to quote.

Please read the FAQ on how to post in this group.
Thanks

Kai-Uwe Bux