exception specification

[Tony Johansson]

Hello!

In this overloaded index operator I have just add this throw() in the header
just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user defined
exception MyOutOfRange is throw.
Can anybody explain that to me?

int& operator[](int i) throw() ; //Here is the declaration

int& Intvektor::operator[](int i) throw()
{
if (i >= size || i < 0)
throw MyOutOfRange("Intvektor:: Positionering som ligger utanför
giltigt område\n");
return array[i];
}

//Tony

[Rapscallion]

Tony Johansson wrote:

In this overloaded index operator I have just add this throw() in the header
just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user defined
exception MyOutOfRange is throw.
Can anybody explain that to me?

You mean, you get no runtime error? Then you are probably using a
Microsoft compiler. MS decided to not fully support the C++ Standard
WRT exception specifications.

[Gianni Mariani]

Tony Johansson wrote:

Hello!

In this overloaded index operator I have just add this throw() in the header
just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user defined
exception MyOutOfRange is throw.
Can anybody explain that to me?

Which compiler were you using ?

[Tony Johansson]

"Gianni Mariani" <gi*******@mariani.ws> skrev i meddelandet
news:Kf********************@speakeasy.net...

Tony Johansson wrote:

Hello!

In this overloaded index operator I have just add this throw() in the
header just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user
defined exception MyOutOfRange is throw.
Can anybody explain that to me?

Which compiler were you using ?

I'm using MS .net

[Tony Johansson]

"Rapscallion" <ra********@spambob.com> skrev i meddelandet
news:11**********************@g49g2000cwa.googlegr oups.com...

Tony Johansson wrote:

In this overloaded index operator I have just add this throw() in the
header
just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user
defined
exception MyOutOfRange is throw.
Can anybody explain that to me?

You mean, you get no runtime error? Then you are probably using a
Microsoft compiler. MS decided to not fully support the C++ Standard
WRT exception specifications.

What does WRT mean?

//Tony

[Artie Gold]

Tony Johansson wrote:

"Rapscallion" <ra********@spambob.com> skrev i meddelandet
news:11**********************@g49g2000cwa.googlegr oups.com...

Tony Johansson wrote:

In this overloaded index operator I have just add this throw() in the
header
just to check what happen when an exception is thrown.
This throw() in the header should means that this method should not throw
anything.
But the strange thing is that I don't get any error when this user
defined
exception MyOutOfRange is throw.
Can anybody explain that to me?

You mean, you get no runtime error? Then you are probably using a
Microsoft compiler. MS decided to not fully support the C++ Standard
WRT exception specifications.

What does WRT mean?

"With Respect To"

HTH,
--ag

--
Artie Gold -- Austin, Texas
http://it-matters.blogspot.com (new post 12/5)
http://www.cafepress.com/goldsays