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template specialization in friend function


I have a class

class x{

public:

template<typename X>
friend X func(X a){
....
}

// I would also want to write the following

template< >
friend double func<double>(double a){
....
}
}
Can someone help on what i am doing wrong?

Thanks,
--j

Jul 22 '05 #1
2 1432

John wrote:
I have a class

class x{

public:

template<typename X>
friend X func(X a){
...
}

// I would also want to write the following

template< >
friend double func<double>(double a){
...
}
}
Can someone help on what i am doing wrong?

Thanks,
--j


If the function definition is inside the class, why does it need to be
a friend?

-shez-

Jul 22 '05 #2
Sorry should have been

class x{

public:

template<typename X>
friend X func(X a);

// I would also want to write the following
template< >
friend double func<double>(double a);
}

Jul 22 '05 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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