Signed?

[JKop]

int a;

short b;

long c;

char d;
According to the Standard, are the above signed or unsigned?
-JKop

[Pete C.]

JKop wrote:

int a;

short b;

long c;

char d;
According to the Standard, are the above signed or unsigned?
-JKop

int, short and long are, char is implementation defined.
If you need a signed or unsigned char, use:
signed char
or
unsigned char

- Pete

[Artie Gold]

JKop wrote:

int a;
Yes.
short b;
Yes.
long c;
Yes.
char d;
Maybe (it's implementation dependent).

According to the Standard, are the above signed or unsigned?

HTH,
--ag
--
Artie Gold -- Austin, Texas

"What they accuse you of -- is what they have planned."

[Pete C.]

Pete C. wrote:

JKop wrote:

int a;

short b;

long c;

char d;
According to the Standard, are the above signed or unsigned?
-JKop
int, short and long are, char is implementation defined.

I mean, int, short and long are signed.

- Pete
If you need a signed or unsigned char, use:
signed char
or
unsigned char

- Pete

[Andrey Tarasevich]

JKop wrote:

int a;

short b;

long c;

char d;
According to the Standard, are the above signed or unsigned?
...

Plain 'int', 'short' and 'long' are always equivalent to 'signed int',
'signed short' and 'signed long', unless used to declare a bit-field (in
which case it is implementation-defined whether they are signed or
unsigned).

A plain 'char' is always a separate type, different (as a type) from
both 'signed char' and 'unsigned char'. However, the value range of char
always coincides with value range of either 'signed char' or 'unsigned
char' (which one - implementation defined). Also, the same comment about
bit-fields applies to plain 'char' as well.

--
Best regards,
Andrey Tarasevich

[JKop]

Conforming to the Standard, should the following compile?:
void Garda(signed short int);

int main(void)
{
short p = 4;

Garda(p);
}
void Garda(short frog)
{
frog = 5;
}

[Andrey Tarasevich]

JKop wrote:

Conforming to the Standard, should the following compile?:
void Garda(signed short int);

int main(void)
{
short p = 4;

Garda(p);
}
void Garda(short frog)
{
frog = 5;
}

Yes, it should. Both declarations of 'Garda' "[...] agree exactly both
in the type of the value returned and in the number and type of
parameters [...]" (8.3.5/3). Additionally, note in 13.1/3 says that
"[...] function declarations that have equivalent parameter declarations
declare the same function [...]".

--
Best regards,
Andrey Tarasevich