Hi,
I'm trying to convert a file reading loop into one using streams. The BSD OS
read API returns the number of bytes read, but istream::read returns itself.
How can I find out the number of bytes actually read?
What the code fragment should do is read up to 1000 bytes into a buffer, or
finish early if reading failed. Just your average read loop.
I have: (this is a simplified version; I know there's no detailed error
checking!)
char buffer[1000];
int bytestoread = 1000;
int totalbytes = 0;
int fd = ... ; // a file descriptor
while( bytestoread )
{
int bytesread = read( fd, buffer, bytestoread );
if( bytesread <= 0 )
break;
buffer += bytesread;
bytestoread -= bytesread;
totalbytes += bytesread;
}
And I want:
char buffer[1000];
int bytestoread = 1000;
int totalbytes = 0;
std::istream& is( ... ); // an istream
while( bytestoread )
{
is.read( buffer, bytestoread ); // << PROBLEM
if( bytesread <= 0 )
break;
buffer += bytesread;
bytestoread -= bytesread;
totalbytes += bytesread;
}
The problem is how can I find out how many bytes were really read? And if
there is, does the mechanism work the same as the OS read API? - ie. Zero to
indicate end, negative for error, etc.
(What I am actually trying to do is interface to libxml2 and get some XML to
be parsed from an istream using xmlCtxtReadIO).
Thanks for any help.
--
Regards,
Steve. 6 3425
Steve wrote: Hi,
I'm trying to convert a file reading loop into one using streams. The BSD OS read API returns the number of bytes read, but istream::read returns itself. How can I find out the number of bytes actually read?
Use istream::readsome.
What the code fragment should do is read up to 1000 bytes into a buffer, or finish early if reading failed. Just your average read loop.
That's a one-liner.
--
Regards,
Buster.
"Steve" <po********@127.0.0.1> wrote in message
news:BCC8CFEE.7183B%po********@127.0.0.1... Hi,
I'm trying to convert a file reading loop into one using streams. The BSD
OS read API returns the number of bytes read, but istream::read returns
itself. How can I find out the number of bytes actually read?
gcount()
It's a clunky part of the iostream API I think, but that's the way you do
it.
The problem is how can I find out how many bytes were really read? And if there is, does the mechanism work the same as the OS read API? - ie. Zero
to indicate end, negative for error, etc.
gcount() returns the number of bytes read, that is never negative.
john
"Buster" <no***@nowhere.com> wrote in message
news:c7**********@news5.svr.pol.co.uk... Steve wrote: Hi,
I'm trying to convert a file reading loop into one using streams. The
BSD OS read API returns the number of bytes read, but istream::read returns
itself. How can I find out the number of bytes actually read?
Use istream::readsome.
readsome only reads characters that are immediately available from the
buffer.
john
John Harrison wrote: "Buster" <no***@nowhere.com> wroteUse istream::readsome. readsome only reads characters that are immediately available from the buffer.
Yes. Thanks a lot; apologies to OP.
--
Regards,
Buster.
On 13/5/04 7:18 am, in article 2g************@uni-berlin.de, "John Harrison"
<jo*************@hotmail.com> wrote: "Steve" <po********@127.0.0.1> wrote in message news:BCC8CFEE.7183B%po********@127.0.0.1... Hi,
I'm trying to convert a file reading loop into one using streams. The BSD OS read API returns the number of bytes read, but istream::read returns itself. How can I find out the number of bytes actually read?
gcount()
It's a clunky part of the iostream API I think, but that's the way you do it.
The problem is how can I find out how many bytes were really read? And if there is, does the mechanism work the same as the OS read API? - ie. Zero
to indicate end, negative for error, etc.
gcount() returns the number of bytes read, that is never negative.
john
Ah, OK, got it. Thanks for that.
Steve.
On 13/5/04 7:29 am, in article c7**********@news6.svr.pol.co.uk, "Buster"
<no***@nowhere.com> wrote: John Harrison wrote: "Buster" <no***@nowhere.com> wrote Use istream::readsome. readsome only reads characters that are immediately available from the buffer.
Yes. Thanks a lot; apologies to OP.
No problem.
That's the mistake I made on my first attempt! :)
Cheers,
Steve. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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