char* combination problem :(

[x]

Im trying to convert a few variables into a string object ( a
character string object). Only I have forgotten how! how
embarrasing....

char *x = (int1 + "/" + int2 + "/" + int3);

whats wrong? int1-3 can equal 0-99...












6e

[Christopher Benson-Manica]

x <ao****@hotmail.com> spoke thus:

Im trying to convert a few variables into a string object ( a
character string object). Only I have forgotten how! how
embarrasing.... char *x = (int1 + "/" + int2 + "/" + int3); whats wrong? int1-3 can equal 0-99...
Simple - you forgot what language you were using. + isn't a catch-all
string creation operator in C++ like it is in various other languages.
If you want a string, declare a string. A decent C++ book and the FAQ
(posted below) will be most helpful.

http://www.slack.net/~shiva/welcome.txt
http://www.parashift.com/c++-faq-lite/











6e

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Rolf Magnus]

x wrote:

Im trying to convert a few variables into a string object ( a
character string object). Only I have forgotten how! how
embarrasing....

char *x = (int1 + "/" + int2 + "/" + int3);

whats wrong?

Doesn't make much sense to add integers and pointers together and write
the result into a pointer. Rembember: char* is not a string, but a
pointer to char. Try:

std::stringstream stream;
stream << int1 << "/" << int2 << "/" << int3;
std::string x = stream.str();

[x]

Rolf Magnus <ra******@t-online.de> wrote in message news:<c5*************@news.t-online.com>...

x wrote:

Im trying to convert a few variables into a string object ( a
character string object). Only I have forgotten how! how
embarrasing....

char *x = (int1 + "/" + int2 + "/" + int3);

whats wrong?

Doesn't make much sense to add integers and pointers together and write
the result into a pointer. Rembember: char* is not a string, but a
pointer to char. Try:

std::stringstream stream;
stream << int1 << "/" << int2 << "/" << int3;
std::string x = stream.str();

the only problem with that is that the function I am tryin to use the
string of characters with requires an input of char*......

[Christopher Benson-Manica]

x <ao****@hotmail.com> spoke thus:

the only problem with that is that the function I am tryin to use the
string of characters with requires an input of char*......

Still easy, if const char* is acceptable - std::string's c_str()
method converts the string to an array of characters, C-style. If you
need a non-const char *, then you'll have to declare an array of
characters and populate it appropriately (I suggest sprintf):

char buf[256]; // larger than required, just make sure it's big enough
// as sprintf will happily overflow the buffer if it
// isn't

sprintf( buf, "%d/%d/%d", int1, int2, int3 );

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.

[Bill Seurer]

x wrote:

the only problem with that is that the function I am tryin to use the
string of characters with requires an input of char*......

You can extract a char* from a string. See the functions in the string
class.