Function matching with constructed args

[Mike Cote]

I have the following function call

p->f(G());

where p is a pointer of type P

and a declaration in scope of

void P::f(G& g);

the gcc 3.2 compiler won't match the call to the function.

If I have

G gTmp;
p->f(gTmp);

with the same function declaration in scope
everything works.

Why? 4 other compilers accept it including gcc 2.6.

Is there a gcc 3.2 option to make this work?

[Ron Natalie]

"Mike Cote" <mi******@earthlink.net> wrote in message news:bc*************************@posting.google.co m...

p->f(G());
void P::f(G& g);

the gcc 3.2 compiler won't match the call to the function.\
Of course. G() is an rvalue. You can not bind an rvalue to a (non-const)
reference. It would match
void P::f(const G& g);
G gTmp;
p->f(gTmp);

with the same function declaration in scope
everything works.
gTmp is an lvalue.
Why? 4 other compilers accept it including gcc 2.6.

They are broken if they do.