In a nutshell, what is the behavior of the assert() macro ***as proscribed
by the C89 Standard*** (which I don't have)? Of course, it doens't appear
in the C++ Standard since it's inherited from C. Hence my inquiry about the
C Standard even though I care about this from a C++ perspective...
Specifically, I'm wondering what the Standard has to say about when the
compiler ignores asserts and when the compiler is to compile them in and
generate code for them. After all, the Standard says nothing debug vs.
release builds... 4 22702
On Wed, 19 Nov 2003 12:50:40 -0700, Dave wrote: In a nutshell, what is the behavior of the assert() macro ***as proscribed by the C89 Standard*** (which I don't have)? Of course, it doens't appear in the C++ Standard since it's inherited from C. Hence my inquiry about the C Standard even though I care about this from a C++ perspective...
Specifically, I'm wondering what the Standard has to say about when the compiler ignores asserts and when the compiler is to compile them in and generate code for them. After all, the Standard says nothing debug vs. release builds...
assert is defined as ((void)0) if the macro NDEBUG is defined at the point
where <assert.h> is included. If NDEBUG is not defined, assert is supposed
to print an error message to stderr and call abort(). The format of the
error message is implementation-defined, but it must include the source
file name and line number (and function name in C99).
"Dave" <be***********@yahoo.com> wrote in message news:<vr************@news.supernews.com>... In a nutshell, what is the behavior of the assert() macro ***as proscribed by the C89 Standard*** (which I don't have)? Of course, it doens't appear in the C++ Standard since it's inherited from C. Hence my inquiry about the C Standard even though I care about this from a C++ perspective...
Specifically, I'm wondering what the Standard has to say about when the compiler ignores asserts and when the compiler is to compile them in and generate code for them. After all, the Standard says nothing debug vs. release builds...
I don't have the C standard either, but in the C++ standard,
17.4.2.1/2 mentions the NDEBUG macro. And my understanding is that
when this macro is not defined, code is generated for an assert, and
when NDEBUG is defined code is not generated.
This ties in with the contents of my implementation's assert.h file.
GJD
EventHelix.com wrote: Checkout the following article for assert handling:
http://www.eventhelix.com/RealtimeMa...y_contract.htm
Sandeep
Their non-debugging macros do not *not* evaluate their arguments; e.g.
ASSERT(strlen(foo) > 10);
gets expanded to
strlen(foo) > 10;
when the _DEBUG flag is not defined. Their code is full of similar
examples where assert macros generate overhead no matter what. Pretty
poor example. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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