HELP

[sonhadorPR]

How do I write the quadratic equation in C++?
Thank You!
SonhadorPR

[osmium]

<so********@gma il.comwrote:

How do I write the quadratic equation in C++?

The same way you write any other equation in C++. Do the algebra with
pencil and paper (if necessary) and type in the equation following the rules
of the language.

[red floyd]

so********@gmai l.com wrote:

How do I write the quadratic equation in C++?
Thank You!
SonhadorPR

Send me your instructor's email address, and I'll send it directly to him.

[Jim Langston]

<so********@gma il.comwrote in message
news:11******** **************@ p79g2000cwp.goo glegroups.com.. .

How do I write the quadratic equation in C++?
Thank You!
SonhadorPR

Quadradic Equation is
ax^2 + bx + c = 0 (where ^2 is squared).

For x this becomes:

-b +/- Sqrt( b^2 - 4ac )
x = ------------------------
2a

Which is known as the Quadratic Formula.

In C or C++ langauge terms this is:
x = (-b + sqrt( b*b - 4 * a * c ) ) / 2 * a;
x = (-b - sqrt( b*b - 4 * a * c ) ) / 2 * a;

(Yes, there are two possible answers.

[Greg]

Jim Langston wrote:

<so********@gma il.comwrote in message
news:11******** **************@ p79g2000cwp.goo glegroups.com.. .

How do I write the quadratic equation in C++?
Thank You!
SonhadorPR

Quadradic Equation is
ax^2 + bx + c = 0 (where ^2 is squared).

For x this becomes:

-b +/- Sqrt( b^2 - 4ac )
x = ------------------------
2a

Which is known as the Quadratic Formula.

In C or C++ langauge terms this is:
x = (-b + sqrt( b*b - 4 * a * c ) ) / 2 * a;
x = (-b - sqrt( b*b - 4 * a * c ) ) / 2 * a;

(Yes, there are two possible answers.

More precisely: there are at most two solutions to the equation.
Depending on the inputs, there may be two, one or no solutions for a
particular equation. The somewhat tricky part is to make sure that the
program can handle all three of these outcomes.

Greg

[Jim Langston]

"Greg" <gr****@pacbell .netwrote in message
news:11******** **************@ p79g2000cwp.goo glegroups.com.. .

>
Jim Langston wrote:

><so********@gm ail.comwrote in message
news:11******* *************** @p79g2000cwp.go oglegroups.com. ..

How do I write the quadratic equation in C++?
Thank You!
SonhadorPR

Quadradic Equation is
ax^2 + bx + c = 0 (where ^2 is squared).

For x this becomes:

-b +/- Sqrt( b^2 - 4ac )
x = ------------------------
2a

Which is known as the Quadratic Formula.

In C or C++ langauge terms this is:
x = (-b + sqrt( b*b - 4 * a * c ) ) / 2 * a;
x = (-b - sqrt( b*b - 4 * a * c ) ) / 2 * a;

(Yes, there are two possible answers.

More precisely: there are at most two solutions to the equation.
Depending on the inputs, there may be two, one or no solutions for a
particular equation. The somewhat tricky part is to make sure that the
program can handle all three of these outcomes.

Greg

True. a == 0.0 would cause problems.

[Howard]

"Jim Langston" <ta*******@rock etmail.comwrote in message news:aAtIg.33

>
In C or C++ langauge terms this is:
x = (-b + sqrt( b*b - 4 * a * c ) ) / 2 * a;
x = (-b - sqrt( b*b - 4 * a * c ) ) / 2 * a;

Don't you need parentheses there, around the "2 * a" part? Division and
multiplication have the same precedence, so as written, the above would
divide by 2, then multiply by a, instead of dividing by (2 * a), right?

-Howard

[Frederick Gotham]

Howard posted:

>
"Jim Langston" <ta*******@rock etmail.comwrote in message news:aAtIg.33

>>
In C or C++ langauge terms this is:
x = (-b + sqrt( b*b - 4 * a * c ) ) / 2 * a;
x = (-b - sqrt( b*b - 4 * a * c ) ) / 2 * a;

Don't you need parentheses there, around the "2 * a" part? Division and
multiplication have the same precedence, so as written, the above would
divide by 2, then multiply by a, instead of dividing by (2 * a), right?

Yes Howard, you're correct.

The formulae should be:

(-b + sqrt(b*b - 4*a*c)) / (2*a);
(-b - sqrt(b*b - 4*a*c)) / (2*a);

--

Frederick Gotham