How can I declare a function that returns a pointer
to one dimensional array ? 12 1762 ju**********@ya hoo.co.in wrote: How can I declare a function that returns a pointer to one dimensional array ?
Like you declare any other funtion, just remember that the scope of
local variables are restricted to within the function. So you have to
return a pointer to dynamically allocated memory, or to a static variable.
cheers,
forayer
--
If you would be a real seeker after truth, it is necessary that at least
once in your life you doubt, as far as possible, all things."
-- Rene Descartes ju**********@ya hoo.co.in writes: How can I declare a function that returns a pointer to one dimensional array ?
Do you really want a pointer to an array, or do you want a pointer to
its first element (which you can then use to access all the elements)?
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Keith Thompson wrote: ju**********@ya hoo.co.in writes: How can I declare a function that returns a pointer to one dimensional array ?
Do you really want a pointer to an array, or do you want a pointer to its first element (which you can then use to access all the elements)?
I want a pointer to an array. (not the pointer to the first element). ju**********@ya hoo.co.in wrote: Keith Thompson wrote: ju**********@ya hoo.co.in writes: How can I declare a function that returns a pointer to one dimensional array ?
Do you really want a pointer to an array, or do you want a pointer to its first element (which you can then use to access all the elements)? I want a pointer to an array. (not the pointer to the first element).
/* BEGIN new.c */
#include <stdio.h>
int (*f(void))[11];
int main(void)
{
printf("f()[0][2] is %d.\n", f()[0][2]);
putchar('\n');
return 0;
}
int (*f(void))[11]
{
static int a[11] = {1, 3, 5, 7};
return &a;
}
/* END new.c */
--
pete ju**********@ya hoo.co.in writes: Keith Thompson wrote: ju**********@ya hoo.co.in writes: > How can I declare a function that returns a pointer > to one dimensional array ?
Do you really want a pointer to an array, or do you want a pointer to its first element (which you can then use to access all the elements)? I want a pointer to an array. (not the pointer to the first element).
Ok. Why?
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
pete wrote: ju**********@ya hoo.co.in wrote: Keith Thompson wrote: ju**********@ya hoo.co.in writes: > How can I declare a function that returns a pointer > to one dimensional array ?
Do you really want a pointer to an array, or do you want a pointer to its first element (which you can then use to access all the elements)? I want a pointer to an array. (not the pointer to the first element).
/* BEGIN new.c */
#include <stdio.h>
int (*f(void))[11];
int main(void) { printf("f()[0][2] is %d.\n", f()[0][2]); putchar('\n'); return 0; }
int (*f(void))[11] { static int a[11] = {1, 3, 5, 7};
return &a; }
/* END new.c */
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