casting

[Baloff]

Hello

I am struggling with this exercise

*************** *************** *************** *************** **********
Define a float variable. Take its address, cast that address to an
unsigned char, and assign it to an unsigned char pointer. Using this
pointer and [ ], index into the float variable and use the
printBinary( ) function defined in this chapter to print out a map
of the float (go from 0 to sizeof(float)). Change the value of the
float and see if you can figure out what\u2019s going on (the float
contains encoded data).

the printBinary.cpp is
#include "printBinar y.h"
#include <iostream>
using namespace std;
void printBinary(con st unsigned char val) {
for(int i = 7; i >= 0; i--)
if(val & (1 << i))
cout << "1";
else
cout << "0";
}

*************** *************** *************** *************** **********

my initial code which puts out the error below is as follows

*************** *************** code*********** *************** ****
#include <iostream>
#include "../printBinary.h"

using namespace std;

int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char) &f;

for (int i = 0; i < sizeof(f); ++i){
ucp[i] = i;
printBinary(f[i]);
}
}


*************** *************** error********** *************** *****
main.cpp: In function `int main()':
main.cpp:8: warning: cast from pointer to integer of different size
main.cpp:8: error: invalid conversion from `unsigned char' to `unsigned char*'
main.cpp:12: error: invalid types `float[int]' for array subscript
make: *** [main.o] Error 1
make: Target `proj1' not remade because of errors.

[Kelly Walker]

"Baloff" <wa****@wash.ed u> wrote in message news:87******** ****@wash.edu.. .

Hello

I am struggling with this exercise

*************** *************** *************** *************** **********
Define a float variable. Take its address, cast that address to an
unsigned char, and assign it to an unsigned char pointer. Using this
pointer and [ ], index into the float variable and use the
printBinary( ) function defined in this chapter to print out a map
of the float (go from 0 to sizeof(float)). Change the value of the
float and see if you can figure out what\u2019s going on (the float
contains encoded data).

the printBinary.cpp is
#include "printBinar y.h"
#include <iostream>
using namespace std;
void printBinary(con st unsigned char val) {
for(int i = 7; i >= 0; i--)
if(val & (1 << i))
cout << "1";
else
cout << "0";
}

*************** *************** *************** *************** **********

my initial code which puts out the error below is as follows

*************** *************** code*********** *************** ****
#include <iostream>
#include "../printBinary.h"

using namespace std;

int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char) &f;

for (int i = 0; i < sizeof(f); ++i){
ucp[i] = i;
printBinary(f[i]);
}
}


*************** *************** error********** *************** *****
main.cpp: In function `int main()':
main.cpp:8: warning: cast from pointer to integer of different size
main.cpp:8: error: invalid conversion from `unsigned char' to `unsigned
char*'
main.cpp:12: error: invalid types `float[int]' for array subscript
make: *** [main.o] Error 1
make: Target `proj1' not remade because of errors.

Make it:

#include <iostream>
#include "../printBinary.h"

using namespace std;

int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char*) &f;
for (int i = 0; i < sizeof(f); ++i){
printBinary(ucp[i]); // Print each byte of float as binary
}
}