How to determinate a integer odd or even

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Hi,
How to determinate a integer odd or even in c#?

[Nicholas Paldino [.NET/C# MVP]]

ad,

Simple:

// See if integer i is odd or even:
bool even = ((i % 2) == 0);

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"ad" <fl****@wfes.tcc.edu.twwrote in message
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Hi,
How to determinate a integer odd or even in c#?

[Jon Skeet [C# MVP]]

ad <fl****@wfes.tcc.edu.twwrote:

How to determinate a integer odd or even in c#?

boolean even = ((x & 1)==0);

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[Michael Klingensmith]

You can determine this by using the modulo operator %

int i = 1;
bool isEven = (i % 2 == 0);
isEven will be false

int i = 2;
bool isEven = (i % 2 == 0);
isEven will be true meaning it is even.

Michael Klingensmith
http://www.seeknsnatch.com

"ad" <fl****@wfes.tcc.edu.twwrote in message
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Hi,
How to determinate a integer odd or even in c#?

[John Timney \(MVP\)]

int nNumber = 5;

if(nNumber % 2 == 0)
{
// even
}
else
{
// odd
}

--
Regards

John Timney (MVP)

"ad" <fl****@wfes.tcc.edu.twwrote in message
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Hi,
How to determinate a integer odd or even in c#?

[Lebesgue]

"Jon Skeet [C# MVP]" <sk***@pobox.comwrote in message
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ad <fl****@wfes.tcc.edu.twwrote:

>How to determinate a integer odd or even in c#?

boolean even = ((x & 1)==0);

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

He asked about C#, not Java, Jon ;-) (OK, I know you are writing much more
code in Java than in C# these days :-) )

[Jon Skeet [C# MVP]]

Lebesgue <le******@gmail.comwrote:

"Jon Skeet [C# MVP]" <sk***@pobox.comwrote in message
news:MP************************@msnews.microsoft.c om...

ad <fl****@wfes.tcc.edu.twwrote:

How to determinate a integer odd or even in c#?

boolean even = ((x & 1)==0);

He asked about C#, not Java, Jon ;-) (OK, I know you are writing much more
code in Java than in C# these days :-) )

Doh :)

bool even = ((x&1)==0);

It's worth knowing the &1 instead of %2 trick, for the occasional
performance-intensive bit of code. It can make quite a difference...

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too