Hi,
When calculating a remainder, R, as a result of X / Y, you wouldn't expect R
to be greater than Y, right? Wrong!
Math.IEEERemainder( double.MaxValue, 1000.0 ) returns 1.99584030953472E+292.
I understand why and how this happens, but the point is that returning a
value that is greater than the divisor, 1000.0, is completely wrong and no
reason could be used as an excuse.
Incidentally, Math.IEEERemainder( double.MaxValue, 100.0 ) returns 0.0 as
expected.
Sunny S 3 1829
Sunny S <su***@neverland.com> wrote: When calculating a remainder, R, as a result of X / Y, you wouldn't expect R to be greater than Y, right? Wrong!
Math.IEEERemainder( double.MaxValue, 1000.0 ) returns 1.99584030953472E+292. I understand why and how this happens, but the point is that returning a value that is greater than the divisor, 1000.0, is completely wrong and no reason could be used as an excuse.
Incidentally, Math.IEEERemainder( double.MaxValue, 100.0 ) returns 0.0 as expected.
This appears to be fixed in .NET 2.0 beta 2 - at least, the above
returns 368, which I believe to be correct.
--
Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Thanks, Jon. 368 is ok At least it looks like a reasonable trade-off between
accuracy and performanceJ
Sunny S.
"Jon Skeet [C# MVP]" <sk***@pobox.com> wrote in message
news:MP************************@msnews.microsoft.c om... Sunny S <su***@neverland.com> wrote: When calculating a remainder, R, as a result of X / Y, you wouldn't expect R to be greater than Y, right? Wrong!
Math.IEEERemainder( double.MaxValue, 1000.0 ) returns 1.99584030953472E+292. I understand why and how this happens, but the point is that returning a value that is greater than the divisor, 1000.0, is completely wrong and no reason could be used as an excuse.
Incidentally, Math.IEEERemainder( double.MaxValue, 100.0 ) returns 0.0 as expected.
This appears to be fixed in .NET 2.0 beta 2 - at least, the above returns 368, which I believe to be correct.
-- Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet If replying to the group, please do not mail me too
Sunny S <su***@neverland.com> wrote: Thanks, Jon. 368 is ok At least it looks like a reasonable trade-off between accuracy and performanceJ
368 is better than okay though - I believe it's the exactly correct
value, given the output of my DoubleConverter which shows the *exact*
value of any double.
--
Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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