urgent help

[John Lee]

Hi,

I have a document
<root>
<name>John</name>
</root>
and the xpath "//name" will return correct node by using
xmldoc.SelectSingleNode(xpath)

and if the document contains a default namespace
<root xmlns="mynamespace">
<name>John</name>
</root>
the xpath "//name" no longer returns the <name> node

Please help!!!

Thanks very much!
John

[Michael C#]

hmm if i remember correctly, you need to qualify your xpath with the
namespace:

xpath = "mynamespace://name"

And you also might need to use an XML NamespaceManager in your app.

"John Lee" <jo***@newsgroup.nospam> wrote in message
news:us**************@TK2MSFTNGP12.phx.gbl...

Hi,

I have a document
<root>
<name>John</name>
</root>
and the xpath "//name" will return correct node by using
xmldoc.SelectSingleNode(xpath)

and if the document contains a default namespace
<root xmlns="mynamespace">
<name>John</name>
</root>
the xpath "//name" no longer returns the <name> node

Please help!!!

Thanks very much!
John

[John Lee]

I could not make it work using nsmgr - please help with code, thanks!
John
"Michael C#" <ho***@boutdat.com> wrote in message
news:%2****************@TK2MSFTNGP09.phx.gbl...

hmm if i remember correctly, you need to qualify your xpath with the
namespace:

xpath = "mynamespace://name"

And you also might need to use an XML NamespaceManager in your app.

"John Lee" <jo***@newsgroup.nospam> wrote in message
news:us**************@TK2MSFTNGP12.phx.gbl...

Hi,

I have a document
<root>
<name>John</name>
</root>
and the xpath "//name" will return correct node by using
xmldoc.SelectSingleNode(xpath)

and if the document contains a default namespace
<root xmlns="mynamespace">
<name>John</name>
</root>
the xpath "//name" no longer returns the <name> node

Please help!!!

Thanks very much!
John

[Kevin Yu [MSFT]]

Hi John,

Here is a simple example that can make it work. HTH.

XmlDocument doc = new XmlDocument();
doc.LoadXml("<root xmlns=\"mynamespace\"><name>John</name></root>");
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("v", "mynamespace");
XmlNode node = doc.SelectSingleNode("//v:name", nsmgr);

Kevin Yu
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