divisiorn problem

[.nLL]

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

[Evertjan.]

..nLL wrote on 16 mei 2008 in microsoft.public.inetserver.asp.general:

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

Use:

<% = "n.nn" %>

;-)
Better lookup vbs: FormatNumber()
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Neil Gould]

Recently, .nLL <no***@here.composted:

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

vbscript:

<%=Round(2/3334, 2)%>

Best,

Neil

[Dave Anderson]

..nLL wrote:

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

That is a string formatting question. And since ASP is not a language, it
must be answered with respect to the language you are using. Check out
VBScript's FormatNumber:
http://msdn.microsoft.com/en-us/libr...sk(VS.85).aspx

or JScript's Number.toFixed():
http://msdn.microsoft.com/en-us/libr...0z(VS.85).aspx

--
Dave Anderson

Unsolicited commercial email will be read at a cost of $500 per message. Use
of this email address implies consent to these terms.

[=?Utf-8?B?T2xkIFBlZGFudA==?=]

"Neil Gould" wrote:

Recently, .nLL <no***@here.composted:

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

vbscript:

<%=Round(2/3334, 2)%>

No, that will actually display simply
0

That's because his number, rounded to 2 decimal places, is 0.00 (no non-zero
digits). But *AS A NUMBER*, there is no difference between 0.00 and just
plain 0.

So when you Response.Write zero, you get simply
0
Nothing more.

You *MUST* use
FormatNumber( 2/33334, 2 )
or equivalent if you really want to see
0.00
displayed.

[Evertjan.]

=?Utf-8?B?T2xkIFBlZGFudA==?= wrote on 26 mei 2008 in
microsoft.public.inetserver.asp.general:

>
"Neil Gould" wrote:

>Recently, .nLL <no***@here.composted:

<%=2/33334%>

returns 5.99988000239995E-05

how can i convert it to a n.nn ?

vbscript:

<%=Round(2/3334, 2)%>

No, that will actually display simply
0

That's because his number, rounded to 2 decimal places, is 0.00 (no
non-zero digits). But *AS A NUMBER*, there is no difference between
0.00 and just plain 0.

So when you Response.Write zero, you get simply
0
Nothing more.

You *MUST* use
FormatNumber( 2/33334, 2 )
or equivalent if you really want to see
0.00
displayed.

You could bake your own,
giving you power over the rounding process:

========= vbs ==============
function myFormatNumber(n,d)
if n<0 then s = "-" else s = ""
n = fix(abs(n)*10^d + 0.5)
if n=0 then s=""
while len(n)<d+1
n = "0"&n
wend
myFormatNumber = s&left(n,len(n)-d)&"."&right(n,d)
if d=0 then myFormatNumber = s&n
end function
===========================



--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Evertjan.]

Evertjan. wrote on 26 mei 2008 in microsoft.public.inetserver.asp.general:

>You *MUST* use
FormatNumber( 2/33334, 2 )
or equivalent if you really want to see
0.00
displayed.

You could bake your own,
giving you power over the rounding process:

========= vbs ==============
function myFormatNumber(n,d)
if n<0 then s = "-" else s = ""
n = fix(abs(n)*10^d + 0.5)
if n=0 then s=""
while len(n)<d+1
n = "0"&n
wend
myFormatNumber = s&left(n,len(n)-d)&"."&right(n,d)
if d=0 then myFormatNumber = s&n
end function
===========================

============== jscript ===========
function myFormatNumber(n,d){
var s = (n<0)?'-':'';
n = Math.floor(Math.abs(n)*Math.pow(10,d)+.5);
if (!n) s='';
if (!d) return s+n;
n += ''; while (n.length<d+1) n = '0' + n;
l = n.length;
return s+n.slice(0,l-d)+'.'+n.slice(l-d);
};
==================================

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[=?Utf-8?B?T2xkIFBlZGFudA==?=]

First of all, that's a fun answer!

But your JS code is using Math.Floor after adding 0.5, which is okay, but
why not just use Math.Round?? Ehhh...but that's a trivial difference.
Nice code. I've seen others do the same thing...in about 4 times as much
code.

[Evertjan.]

=?Utf-8?B?T2xkIFBlZGFudA==?= wrote on 26 mei 2008 in
microsoft.public.inetserver.asp.general:

First of all, that's a fun answer!

[please always quote on usenet]

Added:

============== jscript ===========
function myFormatNumber(n,d){
var s = (n<0)?'-':'';
n = Math.floor(Math.abs(n)*Math.pow(10,d)+.5);
if (!n) s='';
if (!d) return s+n;
n += ''; while (n.length<d+1) n = '0' + n;
l = n.length;
return s+n.slice(0,l-d)+'.'+n.slice(l-d);
};
==================================

But your JS code is using Math.Floor after adding 0.5, which is okay,
but why not just use Math.Round??

Because as I said,
I want complete control over the rounding process.
And I want to be able to use a decimal point or decimal comma,
And I want to be able to set the minus behind the numberstring
or have a &nbsp; filler character where and if there is no minus sign,
or use a + character.

All this is possible if you do your own number to string formatting.

Ehhh...but that's a trivial
difference. Nice code. I've seen others do the same thing...in about
4 times as much code.

As I stem from prehistoric assembler coding time,
writing compact code still feels as the ultimate bliss.

What is missing is error testing for noninteger or negative values of the
number of decimals parameter.

By adding as the first line in the js function:

if (d===undefined) d = 2;

It that parameter defaults to a 2 decimal format.

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)