InStr Help

[Graham Mattingley]

How do I use InStr to find the string d="1"

I have tryed

InStr(text,"d="1"") and it does not work

I have tryed a few other variations and I cant get it to work

Thanks

Graham

[Evertjan.]

Graham Mattingley wrote on 10 nov 2003 in
microsoft.public.inetserver.asp.general:

How do I use InStr to find the string d="1"

I have tryed

InStr(text,"d="1"") and it does not work

I have tryed a few other variations and I cant get it to work

" is clientside html, not serverside asp vbs

try:
s = "d=""1"""

InStr(text,s)

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Steven Burn]

InStrRev(stringtocheck, "d=1")

--

Regards

Steven Burn
Ur I.T. Mate Group
www.it-mate.co.uk

Keeping it FREE!

Disclaimer:
I know I'm probably wrong, I just like taking part ;o)
Graham Mattingley <gr****@technocom.com> wrote in message
news:bo******************@news.demon.co.uk...

How do I use InStr to find the string d="1"

I have tryed

InStr(text,"d=&quot;1&quot;") and it does not work

I have tryed a few other variations and I cant get it to work

Thanks

Graham

[dlbjr]

strFind = "d=" & Chr(34) & "1" & Chr(34)
InStr(text,strFind)

-dlbjr

Discerning resolutions for the alms

[Chris Barber]

OK, basically the string:

d="1"

needs to have the doublequotes 'doubled' up when placed directly into a
string variable as:

pstrStringToFind = "d=""1"""

So you can now do:

If InStr(pstrSomeString, pstrStringToFind) > 0 Then
'String Found
End If

You can also do:

pstrStringToFind = "d=" & Chr(34) & "1" & Chr(34)

since Chr(34) is in fact a doublequote character.

It's a pity that VBScript doesn't support the use of either ' or " as the
text delimiter (bad choice of comment delimiter really) cos in JavaScript
it's dead easy:

var pstrString = 'd="1"';

A *lot* easier on the eye.

Regards,

Chris.

"Graham Mattingley" <gr****@technocom.com> wrote in message
news:bo******************@news.demon.co.uk...
How do I use InStr to find the string d="1"

I have tryed

InStr(text,"d=&quot;1&quot;") and it does not work

I have tryed a few other variations and I cant get it to work

Thanks

Graham