Need Blank Lines in Report

[shyjukj]

I have attached my MS Access File. After data entered in Job Card (including Invoice Tab) and When Print Invoice Button is created it prints the invoice. BUT I NEED MINIMUM 10 LINE ITEMS IN THE INVOICE DETAIL. Suppose there are 2 line items with data balance 8 can be blank lines, if 9 line are with data balance 1 blank line and if there are 15 line items all 15 with out any blank line should be there in the invoice print out. I tried all the way. But nothing succeeded. I am very bad in VB Codes.

Someone please help me with this. I have uploaded my file.

[Rabbit]

Sorry, but as a rule of thumb, I do not download attachments from strangers.

You don't need any VBA code. What you can do is create a table with 10 blank rows and use a union all query to append the number of rows you need.

[shyjukj]

Thank you Rabbit for your reply.... There is a small change in my concept. After reading your reply only I realized, if there are more than 10 line data in the invoice, it would display only 10 line items and the invoice will be incomplete.
Kindly help.

[zmbd]

in which case you'll want to review the following thread:
http://bytes.com/topic/access/answer...-empty-records
We're still using a union query in this thread, we're simply appending a enough blank records to fill out the report detail, in the above thread, 15 total, for your's 10 total.

If you need more help understanding the above thread's contents, please start a new thread with reference back to this thread and/or the thread above.

[shyjukj]

Thank you Zmbd.... But it will restrict the line to 10 irrespective of number of data, right? Suppose there are 13 data in the record, it will record only the first 10 records and will omit the balance 3 data lines. Hence the report will be incomplete. What to do if I need minimum 10 lines and if there are 13 lines in data, then I need all 13 in the report.
Please help.

[zmbd]

Why don't you actully run the query and the report as the link has shown for the union query; doing so will answer your question. (^_^)

[shyjukj]

I tried it yesterday,.... created a blank table same as my primary table then created a query like below;

SELECT Null AS [IDField]
     , *
FROM   [tblEvidence]
UNION ALL
SELECT [IDField]
     , Null
     , Null
     , ... etc
FROM   [tblBlank]
WHERE  ([IDField] Between ((((SELECT Count(*)
                             FROM   [tblEvidence]) - 1) Mod 15) + 2) And 15)
 

It gave some error message due to the word "etc".

Then I tried the other code;

SELECT Null AS [IDField]
   , *
FROM [tblEvidence]
   UNION ALL
SELECT [IDField]
FROM   [tblBlank]
WHERE  ([IDField]
   Between ((((
      SELECT Count(*)
      FROM   [tblEvidence]) - 1) Mod 15) + 2)
    And 15)

Then it returned an error, column in both tables are not same... but i had given the same column like my primary table....

Above all I am just a beginner in MS Access and just copy paste VBA Codes without any idea :)

Help would be highly appreciated.

[zmbd]

Above all I am just a beginner in MS Access and just copy paste VBA Codes without any idea :)

And that is a problem

- If you understood what you were doing, you would have realized that "etc..." isn't a valid SQL construct.

- If you had actually read the thread that I linked you to, you would have seen in both in NeoPa and my own post how to handle the column issue. You would also understand how your second SQL script is malformed.

I can understand that it can be frustrating to have people tell you that you need to learn something instead of just coughing up the answers; however, that does you no good and and makes us nothing more than unpaid programmers.

What I am going to send you via PM is a listing of tutorials and reference links. You must have a mastery of the first tutorial in order to have the basic knowledge base needed to get Access to do anything useful - and without this mastery, the more advanced concepts as you have asked for here will never make sense to you.

Check your Bytes.com Inbox in about 5 minutes from this posting time.

[shyjukj]

Thank you so much Zmbd.