Looks like you've got an offer of code already but I'll give a hint to
anyone that wants to figure this out themselves.
using System.Text.RegularExpressions;
split the number into an integer and a fraction by using the space
between them, split the numerator and denominator by using the "/"
between them, divide the numerator by the denominator, then add the integer.
in Perl this could be done like so; (the regular expression will be
similar in C#, that is why I am showing you this)
my $fraction = "2 1/2";
my ($int, $num, $den) = $fraction =~ m|(\d+) (\d+)/(\d+)|;
print $int + ($num/$den);
this prints "2.5". In Perl variable types are pretty insignificant, its
smart enough to know when you need a double, and it auto converts. Perl
makes you LAZY, don't use it unless you need development speed.
Enough about Perl.
the bit between the "m|" and the "|" will be important to you.
jeremiah();
Valerie Hough wrote:
Is there a C# class that will help convert strings that include fractions
( "2 1/2" e.g.) to doubles ? Convert.ToDouble() throws an invalid input
format exception.
Obviously I can write code to do it but this seems like a fairly normal
thing to want to do and I would expect C# to have already built in support.
Can anyone help? Even unmanaged code would do.
Brian Hough
