Hi,
I have problems in trying to '++' an array value.
Every time I find a city I add it in the array,
and if I find it many times I increment the value (counter)
of the city. Here's the code:
$address = "http://www.cji.co.il/bw040609.txt";
$address_local = "bw040609.t xt";
$lines = file($address_l ocal);
$heading = "Companies covered in this CJI report:";
$heading_line = 0;
$towns = array();
for($i=0; $i<count($lines ); $i++) {
$pos = strpos($lines[$i], "Location: ");
if($pos !== false) {
list($loc,$town ) = preg_split("/: /", $lines[$i]);
if(in_array($to wn, $towns)) {
$towns[$town] = 1;
echo "Town added: $town<br>";
}
else {
$towns[$town]++;
echo "Town added: $town<br>";
}
}
}
foreach($towns as $key => $value) {
print "$key => $value<br>";
}
The output is like this:
Notice: Undefined index: Ramat Hasharon in
C:\Programs\wor k\jobs\index.ph p on line 40
Town added: Ramat Hasharon
Notice: Undefined index: North in C:\Programs\wor k\jobs\index.ph p on line 40
Town added: North
Town added: North
Notice: Undefined index: Location in C:\Programs\wor k\jobs\index.ph p on
line 40
Town added: Location
Town added: Location
Town added: North
Town added: North
and so on...
It complains about an undefined index.
Any idea why it does that?
Shmuel. 5 1899
Then the result will be 1 for each town even if there are many hits.
Pedro Graca wrote: Shmuel wrote: (snip)
if(in_array($to wn, $towns)) {
Shouldn't this be reversed?
if(!in_array($t own, $towns)) {
$towns[$town] = 1; echo "Town added: $town<br>";
} else { $towns[$town]++; echo "Town added: $town<br>"; }
(snip)
Shmuel wrote: Then the result will be 1 for each town even if there are many hits.
use array_key_exist s() instead of in_array() http://www.php.net/array_key_exists
========
pedro$ cat xx.php
<?php
$towns = array();
$towns['x'] = 3;
$town = 'x';
if(!array_key_e xists($town, $towns)) {
$towns[$town] = 1;
echo "Town added: $town<br>\n";
} else {
$towns[$town]++;
echo "Town added: $town<br>\n";
}
$town = 'y';
if(!array_key_e xists($town, $towns)) {
$towns[$town] = 1;
echo "Town added: $town<br>\n";
} else {
$towns[$town]++;
echo "Town added: $town<br>\n";
}
print_r($towns) ;
?>
pedro$ php xx.php
Town added: x<br>
Town added: y<br>
Array
(
[x] => 4
[y] => 1
)
========
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Shmuel wrote: Pedro Graca wrote: Shouldn't this be reversed?
Then the result will be 1 for each town even if there are many hits.
No, Pedro is right - your code is wrong, or isn't it 1 for each town
even if there are many hits?
Greetings Christian
Do this:
for($i=0; $i<count($lines ); $i++) {
$pos = strpos($lines[$i], "Location: ");
if($pos !== false) {
list($loc,$town ) = preg_split("/: /", $lines[$i]);
@$towns[$town] += 1;
}
}
"Shmuel" <sd*@nic.fi> wrote in message
news:lE******** ********@reader 1.news.jippii.n et... Hi, I have problems in trying to '++' an array value. Every time I find a city I add it in the array, and if I find it many times I increment the value (counter) of the city. Here's the code:
$address = "http://www.cji.co.il/bw040609.txt"; $address_local = "bw040609.t xt"; $lines = file($address_l ocal);
$heading = "Companies covered in this CJI report:"; $heading_line = 0;
$towns = array();
for($i=0; $i<count($lines ); $i++) {
$pos = strpos($lines[$i], "Location: "); if($pos !== false) { list($loc,$town ) = preg_split("/: /", $lines[$i]); if(in_array($to wn, $towns)) { $towns[$town] = 1; echo "Town added: $town<br>";
} else { $towns[$town]++; echo "Town added: $town<br>"; } }
}
foreach($towns as $key => $value) { print "$key => $value<br>"; } The output is like this:
Notice: Undefined index: Ramat Hasharon in C:\Programs\wor k\jobs\index.ph p on line 40 Town added: Ramat Hasharon
Notice: Undefined index: North in C:\Programs\wor k\jobs\index.ph p on line
40 Town added: North Town added: North
Notice: Undefined index: Location in C:\Programs\wor k\jobs\index.ph p on line 40 Town added: Location Town added: Location Town added: North Town added: North
and so on...
It complains about an undefined index. Any idea why it does that? This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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