XSL Attribute Test

[prao2005]

Q) How to check whether the value of an attribute is not null or if the lenght of characters in the value of an attribute is greater than 0?

Solution applied -->
s0SelectedSite is an attribute of a class or a column of a table.

<xsl:if test="string-length(@s0SelectedSite) &gt; '0'">
<tr>
  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td>
  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td>
</tr> 
</xsl:if>

In the above, the value of s0SelectedSite exists but still the lines are not getting printed.

For eg. It should display the following:-

Selected Site: Singapore
Please let me know if something is wrong.

[Dormilich]

<xsl:apply-templates select="DBE:Attribute[@name='s0SelectedSite']"/>

what is that supposed to do?

[prao2005]

Its purpose is to display the the value of s0SelectedSite attribute which belong to a class/object.

[Dormilich]

does it do what it is supposed to do?

[prao2005]

Thanks to all....

0
I tried this way now --> It worked for me :

<xsl:choose>
  <xsl:when test="string-length(DBE:Attribute[@name='s0SelectedSite']/node()) &gt; 0"> 
    <table>
...<tr> 
  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td> 
  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td> 
</tr>
    </table>
  </xsl:when>
  <xsl:otherwise>
    <table>
...<tr> 
  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td> 
  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td> 
</tr>
    </table>
  </xsl:otherwise>
</xsl:choose>

It works now.....i get the field empty incase of no value....incase of value i get the selected site value.

[Dormilich]

@prao2005
that is correct behaviour. if you want to skip empty values, you have to test for them before.