Select element value based on attribute values in XML.

[abhijeetraje]

I am applying XSLT to WSDL to generate html pages.

now, as WSDL is not having comprehensive details, i am adding XML documentation (.NET) as well in XSLT.
like this..

<xsl:variable name="ddoc" select="document('CustomerCare.ManageMeterReads.ServiceContracts.xml')" />

Here is the XML documentation....

<?xml version="1.0"?>
<doc>
<assembly>
<name>CustomerCare.ManageMeterReads.ServiceContracts</name>
</assembly>
<members>
<member name="T:abc.pqr.test.CustomerCare.ManageMeterReads.ServiceContracts.CommonEntities.EmployeeID">
<summary>
Holds the configuration details for each Service.
</summary>
</member>
</members>
</doc>

WSDL is having element types e.g. EmployeeID ( i am able to extract the element types from XSDL, storing it in $type-local-name) however the description of that element is in above xml. my requirement is to get the "summary" element from above xml based on the member/name attribute.

WSDL just contain "EmployeeID" not full value "T:abc.pqr.test.CustomerCare.ManageMeterReads.Serv iceContracts.CommonEntities.EmployeeID".

I tried this... but not working...

<xsl:value-of select="$ddoc/doc/members/member[contains($ddoc/doc/members/member/@name,$type-local-name)]/summary"/>

[jkmyoung]

Look for the name attribute at the node you currently are condition testing.
[contains(@name,$type-local-name)]

[abhijeetraje]

I tried this...
<xsl:value-of select="$ddoc/doc/members/member[@name='contains(@name,$type-local-name']/summary"/>

however its not showing any results.

i want to extract summary element in $ddoc where attribute "name" is having value that contains $type-local-name'

[Dormilich]

I think jkmyoung was rather proposing this

<xsl:value-of select="$ddoc/doc/members/member[contains(@name,$type-local-name)]/summary"/>