XSLT strips bullet tag

I have the following XML:

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 <eventsTable>

<eventRec> <dateTime>06/01/2009 21:36:43</dateTime> <rawDateTime>1231277803</rawDateTime> <type>Event</type> <source>GSC</source> <eventId>GSC_USER_CONFIG</eventId> <assAlrm>--</assAlrm> <username>walt</username> <desc>GSC Users<bullet>User Configuration Change</bullet> <bullet> SUBMITTED: walt logged in from IP address 172.16.207.22</bullet> </desc> </eventRec>

<eventRec> <dateTime>05/01/2009 21:36:43</dateTime> <rawDateTime>1231277803</rawDateTime> <type>Event</type> <source>GSC</source> <eventId>GSC_CONFIG</eventId> <assAlrm>--</assAlrm> <username>walt</username> <desc>System switched to sleep mode</desc> </eventRec>

<eventsTable>

I've developed the following XSL but it seems to strip out the bullets. So I get a displayed desc field like "GSC UsersUser Configuration Change SUBMITTED: walt logged in from IP address 172.16.207.20 " How would I edit my code to include the bullets or even just linebreaks? To get something like:

GSC Users

User Configuration Change
SUBMITTED: walt logged in from IP address 172.16.207.20

XSL:

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 <xsl:output method="html"/>
 
<xsl:template match="/">

  <html>

<body>

  <table id="eventsTable" title="Events Log"><thead>

      <tr>

        <th align="center">TimeStamp</th>

        <th align="center">Type</th>

        <th align="center">Source</th>

        <th align="center">ID</th>

        <th align="center">Associated Alarm</th>

        <th align="center">Username</th>

        <th align="center">Description</th>

      </tr></thead><tbody>

      <xsl:for-each select="eventsTable/eventRec">

        <xsl:sort select="position()" data-type="number" order="descending"/>

        <xsl:if test="position() mod 2 = 1">

          <tr class="even">

            <td align="center"><xsl:value-of select="dateTime"/></td>

            <td><xsl:value-of select="type"/></td>

            <td><xsl:value-of select="source"/></td>

            <td><xsl:value-of select="eventId"/></td>

            <td align="center"><xsl:value-of select="assAlrm"/></td>

            <td align="center"><xsl:value-of select="username"/></td>

            <td><xsl:value-of select="desc"/></td>
 
          </tr>

        </xsl:if>

        <xsl:if test="position() mod 2 = 0">

          <tr class="odd">

            <td align="center"><xsl:value-of select="dateTime"/></td>

            <td><xsl:value-of select="type"/></td>

            <td><xsl:value-of select="source"/></td>

            <td><xsl:value-of select="eventId"/></td>

            <td align="center"><xsl:value-of select="assAlrm"/></td>

            <td align="center"><xsl:value-of select="username"/></td>

            <td><xsl:value-of select="desc"/></td>

          </tr>  

        </xsl:if>
 
      </xsl:for-each>

    </tbody></table>

  </body></html>

</xsl:template>
 
</xsl:stylesheet>

Jan 8 '09 #1

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6186

jkmyoung

2,057

Expert 2GB

This is a little hard because we need to know: Do all bullet nodes start a list? Are there multiple lists in a single description? (hard to deal with). This code uses linebreaks instead.

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<td><xsl:apply-templates select="desc/node()"/></td> 
 
<xsl:template match="bullet">

<br/>- <xsl:value-of select="."/>

<xsl:if test="not (generate-id(following::node()) = generate-id(following::*)) or position() = last()"> 

<br/>

</xsl:if>

</xsl:template>

Jan 8 '09 #2

asianmike

@jkmyoung
Thanks for the quick reply.
Unfortunately when I make that change, it still doesn't display the bullets. But when I play with the xml a little bit and change the <bullet> tags to <li> tags it does display those. That may be the best solution if I don't receive any more suggestions about the bullet tags.

Jan 8 '09 #3

jkmyoung

2,057

Expert 2GB

Sorry, edited my reply because I realized <bullet> wasn't a html node.

Jan 8 '09 #4

asianmike

Heh, yea I was doing the same thing.

The latest code seems to work great. Thanks for the help!

Jan 8 '09 #5

XSLT strips bullet tag

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