To delete a unwanted sub element using xsl

[radhakrishnanrs]

I have xml like

<root>
<parent>
<child1>Text</child1>
</parent>
</root>

I want to delete the unwanted sub element <child1> and output would be like <parent>Text</parent>.

Thanks in advance.

[Dormilich]

if the xml is that simple you can simply rewrite it.

<xsl:template match="parent"> // or any convenient xpath/name depending on the situation
  <parent>
    <xsl:value-of select="child1/text()"/>
  </parent>
</xsl:template>

regards

[radhakrishnanrs]

if the xml is that simple you can simply rewrite it.

<xsl:template match="parent"> // or any convenient xpath/name depending on the situation
  <parent>
    <xsl:value-of select="child1/text()"/>
  </parent>
</xsl:template>

regards

Thanks for info but it is not a simple xml file. It is a big xml file with lot of elements. I have tried the above sample, but it is not resulting the desired output. The xml file is actually looks like:

<site.info number="009" snumber="0122" wnumber="AtoZ" type="text"><ital>Rose,</ital> running text</site.info>

here it want to remove the element <ital>, I am using this xsl file as pre cleanup process.

Thanks in advance

[Dormilich]

Thanks for info but it is not a simple xml file. It is a big xml file with lot of elements. I have tried the above sample, but it is not resulting the desired output.

the problem lies in the <template>'s match attribute. if you want to filter it from a more complex xml you'll probably need to copy the xml but those elements and insert the corrected elements.
some general code for xsl copy you'll find here in some of the threads (I'll look up some of them later). the principle is something like

<xsl:template match="node() | @*">
  <xsl:copy select="."/>
</xsl:template>

of cause this is without filter.

<xsl:template match="node()[not(ital)]">
// ...
// add attribute copy

this will exclude any elements with a <ital> child element from copying, now insert the just excluded elements

<xsl:template match="node()[ital]">
// code similar to the already posted

note: this is a rough sketch of what I would do, still need to look up the exact code.

regards

[Dormilich]

some general code for xsl copy you'll find here in some of the threads (I'll look up some of them later).

https://bytes.com/showthread.php?t=842976
https://bytes.com/showthread.php?t=841347
**********

[jkmyoung]

Assuming you're just filtering out the ital nodes:

<xsl:template match="ital">
  <xsl:apply-templates/> <!-- apply-templates but do not copy the node -->
</xsl:template>
 
<xsl:template match="*"> <!-- copy template -->
  <xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>
 

[radhakrishnanrs]

Thanks all, it Worked correctly:)