<Need Help>How to select tagvalues based on multiple conditions in XSLT?

[njsimha]

Hi,
I have a query regarding the selection of a particular tag based on a condition.
In the following XML code:

 <root>
 
 <template1>
 <elem1>1000</elem1>
 <elem2>
 <subelem1>65</subelem1>
 </elem2>
 </template1>
 
 <template1>
 <elem1>2000</elem1>
 <elem2>
 <subelem1>45</subelem1>
 </elem2>
 </template1>
 
 <template2>
 <type1>
 <tag1>1000</tag1>
 </type1>
 
 <rule>
    <match>
       <id>10</id>
    </match>
    <tag1> 1000 </tag1>
 </rule>
 
 <rule>
    <match>
       <id>20</id>
    </match>
    <tag1>1000</tag1>
 </rule>
 
 </template2>
  </root>
 
 

Using XSLT,I want to allow all the /root/template2/rule/match/id= only 10 or 30 where /root/template2/rule/tag1 = /root/template2/type1/tag1 and /root/template1/elem1 = /root/template2/type1/tag1 whose /root/template1/elem2/subelem1 > 50

For the above code,error has to be thrown because /root/template2/rule/match/id = 20 whose tag1=1000 and there is a template1 whose elem1=1000 and whose subelem1 is 65(which is >50)

Please let me know the XSLT piece of code how to achieve this conditional selection

Thanks,

[jkmyoung]

So just to be clear, the subelem1 in template1 have to match a given template2 if there is a rule for the elem1? Also, do you use template2/type1/tag1 for the match or template2/rule/match/tag1 for the match?
Does the >50 matter?

<xsl:for-each select="/root/template1">
   <xsl:variable name="elem1" select="elem1"/>
  <xsl:variable name="subelem1" select="elem2/subelem1"/>
  <xsl:if test="/root/template2/type1/tag1[.=$elem1]">
     <xsl:if test="not(/root/template2[type1/tag1.=$elem1]/rule/match[id = $subelem1]">
      THROW ERROR HERE.
     </xsl:if>
  </xsl:if>
</xsl:for-each>
 

[Dormilich]

Hey njsimha,

from your previous thread you should have already learned how to address the most of your conditions.

just to remember, you can put any number of conditions on an XPath:

element[expr1 = x][expr2 != y][expr3[condition] = z]

regards