5
Hello All,
I am stuck with a problem. I have an xml file as follows
<parent>
<publisher>
<name>somename</name>
<book1>data1</book1>
<book2>data2</book2>
<book3>data3</book3>
<book4>data4</book4>
</publisher>
</parent>
I want to tranform this xml file into html file. I have written an xsl file for the transformation which is as follows
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="somename">
</xsl:param>
<xsl:template match="/">
<html>
<head><title>Publisher Details</title></head>
<body>
<table border="1">
<xsl:for-each select="parent/publisher[name=$somename]/*">
<xsl:if test="local-name()!='book1' or local-name()!='book3'">
<tr>
<td><b><xsl:value-of select="local-name()" /></b></td>
<xsl:if test="not(current()/*)">
<td><xsl:value-of select="current()" /></td>
</xsl:if>
<xsl:for-each select="current()/*">
<tr>
<td><b><i><xsl:value-of select="local-name()" /></i></b></td>
<td><xsl:value-of select="current()" /></td>
</tr>
</xsl:for-each>
</tr>
</xsl:if>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
I want to tranform only some of the elements of xml file into html and not all, therefore I have specified the condition
<xsl:if test="local-name()!='book1' or local-name()!='book3'">
where I do not want book1 and book3 to be included in transformed file.
But the problem is this approach does not work.
Interestingly when I specify only 1 condition, it works, but not when I have more than 1 condition.
Kindly suggest me what I am doing wrong here...or suggest me a good approach to solve such a probelm.
